Answer:
HECF
Step-by-step explanation:
I FOUND THIS FUN BUT I DONT KNOW IF ITS RIGHT
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
for question #1 the answer is: x=2, x=-1
question 9: answer is B
question 10: answer B
Decimal : 0.53
percentage : 53%
