3 years ago

How do you write 3 2/4 as a fraction greater than 1

Mathematics

2 answers:

Ymorist [56]3 years ago

6 0

You can write it as 14/4

Alenkinab [10]3 years ago

6 0

the correct answer is 14/4

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Please help ASAP 40 pts

natali 33 [55]

Answer:

x=2

Step-by-step explanation:

We know AC = BC since this is an isosceles triangle

6 = 2x+2

Subtract 2 from each side

6-2 =2x+2-2

4 =2x

Divide each side by 2

4/2 =2x/2

2=x

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3 years ago

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What is nine times for a total loss of 15 3/4 yards

love history [14]

Try feet /cm or inches

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3 years ago

Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

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3 years ago

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solong [7]

Answer is -44+x^2 . First you need to evaluate the equation and get 5+x^2-49 then u calculate it and your final answer is -44+x^2

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Which number line shows the estimate of square root of 47 in the correct interval of integers

mr_godi [17]

Answer:

Step-by-step explanation:

Because yes

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