Step-by-step explanation:
Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC
To prove = ∠3= 49°
Solution:
In figure, m∥n cut by traversal t.
So, ∠DEF = ∠ABC(alternative exterior angles)
∠1 + ∠2 = ∠4 + ∠5
∠ABC = ∠1 + ∠2 = 50° + 48° = 98°
Also given that s bisect angles ∠ABC.
∠4 = ∠5
∠ABC = ∠4 + ∠5 = 98°
∠4 + ∠4 = 98°
2∠4 = 98°
∠4 = 49°
∠4= ∠3 = 49° (vertically opposite angles)
∠3 = 49° ,hence proved
Let x= $4.75 shares
600-x- $5.00 shares
4.75x + 5 (600-x)= 2912.50
distribute and remove ( )
4.75x +3000-5x= 2912.50
combine like terms
-,25x + 3000= 2912.50
subtract 3000 from both sides
-.25x= -87.5
divide by -.25
x=350 shares @ $4.75
600-350= 250 shares @ $5,00
hope this helps
We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
Answer: the scale factor is 3/4
Step-by-step explanation:
4/9(2n)+4/9(-3)
(4x2/9)n+(4 x -3)/9
(8/9)n -12/9
8/9n-4/3
