Answer:
I could do 1 and 3
1) 2x-3y=-2 ....1
-
2x+y=14......2
=-4y=-16
y=4
<u>Substitute</u><u> </u><u>(</u><u>y</u><u>=</u><u>4</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
2x-3 (4)=-2
2x-12=-2
2x=-2+12
2x=10
×=5
3) 5x+5y=20....1
-
-3x+5y=4......2
=8x=16
x=2
<u>S</u><u>ubstitute</u><u> </u><u>(</u><u>x</u><u>=</u><u>2</u><u>)</u><u> </u><u>into</u><u> </u><u>equation</u><u> </u><u>1</u>
<u>5</u><u> </u><u>(</u><u>2</u><u>)</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>10</u><u>+</u><u>5y</u><u>=</u><u>20</u>
<u>5y</u><u>=</u><u>20-10</u>
<u>5y</u><u>=</u><u>10</u>
<u>y</u><u>=</u><u>2</u>
The measure of angle ABD would be 77 degrees; 132-55=77.
Temperature at mid-night
=235+(-485)
=-250 degrees, whatever the unit was (C,F, R, K).
K= 3 is the starting value for k. The number six means the sum of 3 to 6.
Replace k with the values and solve:
K = 3 = -2(3) + 5 = -1
K = 4 = -2(4) + 5 = -3
K = 5 = -2(5) + 5 = -5
K = 6 = -2(6) + 5 = -7
Sum = -1 + -3 + -5 + -7 = -16
Sum = -16
<h2>
<em>Answer:</em></h2><h3>
<em>2</em><em>4</em><em>x</em><em>^</em><em>4</em><em>+</em><em>3</em><em>2</em><em>x^3</em><em>+</em><em>3</em><em>2</em><em>x</em><em>^</em><em>2</em><em>+</em><em>1</em><em>6</em><em>x</em><em>+</em><em>1</em><em>0</em></h3>
<em>please</em><em> see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em>
<em>Hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>