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Artist 52 [7]
2 years ago
6

Help with this homework

Mathematics
1 answer:
Stolb23 [73]2 years ago
5 0
It is just white so I can’t help I’m sorry
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Which expressions are equivalent to 2 (three-fourths x + 7) minus 3 (one-half x minus 5)? Check all that apply.
Mariulka [41]

Answer:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

Step-by-step explanation:

The original expression given in the text is

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)  (1)

And we want to check to what other expressions is equivalent. First of all, we solve it by writing explicitely each term:

\frac{3}{2}x+14-\frac{3}{2}x+15 (2)

Let's verify each of the other expressions separately. For the first one:

2(\frac{3}{4}x+7)+(-3)(\frac{1}{2}x+(-5))

We see that this is equivalent to expression (1), since the first half is identical, while in the second one, the combination "+-" can be simply written as "-", so we get

2(\frac{3}{4}x+7)-3(\frac{1}{2}x-5)

Which is equivalent to (1).

For the 2nd one:

2(\frac{3}{4}x)+2(7)+3(\frac{1}{2}x)+3(-5)

This is not equivalent. In fact, here we have applied the distributive property to each term: however, the 3rd and 4th term are not correct, because the (3) must be negative (-3), as in the original expression.

If we write it explicitely in fact, we get

\frac{3}{2}x+14+\frac{3}{2}x-15

Which is different from (2).

For the 3rd one:

2(\frac{3}{4}x)+2(7)+(-3)(\frac{1}{2}x)+(-3)(-5)

This one is equivalent. In fact, here we have applied the distributive property correctly. By solvign each term we get:

\frac{3}{2}x+14-\frac{3}{2}x+15

8 0
3 years ago
Read 2 more answers
Which of the following is a graph of y < x + 3?
Alexeev081 [22]

Answer: it’s D :)

Step-by-step explanation: I was wondering if you could help me with my recent chemistry question I’ve posted it over and over and nobody answered it seriously they only say random stuff for points or search it up but it’s not the right answer.. please help me if not that’s fine.

6 0
2 years ago
1. The numbers ______ and _____ are respectively the additive and multiplicative identities of rational numbers
miss Akunina [59]

Answer:  0 and 1, in that order

The numbers <u>   0   </u> and <u>   1   </u> are respectively the additive and multiplicative identities of rational numbers.

===========================================================

Explanation:

The additive identity is 0 because adding 0 to any number leads to the original number. For instance, 7+0 = 7. In general we can say x+0 = x or we could also say 0+x = x.

The multiplicative identity is 1 because multiplying 1 with anything leads to that original number. Example: 1*5 = 5 or 9*1 = 1. The general template is x*1 = x which is the same as saying 1*x = x.

These ideas not only apply to rational numbers, but to real numbers as well.

8 0
2 years ago
Find the distance between the points. (Round your answer to two decimal places. (9.7, - 2.8), (- 3.2, 8.8)
Dmitry [639]

Answer:

Rounding it to two decimal places, we get distance, d=17.35

Step-by-step explanation:

Given:

The two points are (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

The distance between the two points can be obtained using the distance formula which is given as:

d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Here, for the points, (9.7, -2.8)\textrm{ and }(-3.2, 8.8)

x_{1}=9.7,x_{2}=-3.2,y_{1}=-2.8,y_{2}=8.8

Therefore, the distance between the points is:

d=\sqrt{(-3.2-9.7)^2+(8.8-(-2.8))^2}\\d=\sqrt{(-12.9)^2+(8.8+2.8)^2}\\d=\sqrt{(12.9)^2+(11.6)^2}\\d=\sqrt{166.41+134.56}\\d=\sqrt{300.97}=17.348

Rounding it to two decimal places, we get d=17.35

7 0
3 years ago
a local charity held a crafts fair selling donated, handmade items. Total proceeds from the sale were 1875. a total of 95 items
Anastasy [175]
55 items sold for $15 each.
40 sold for $25 each.
3 0
3 years ago
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