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natita [175]
3 years ago
6

PLEASE HELP MATH QUESTION 99 POINTS HELP ASAP PLEASE LOOK AT LINKED IMAGE FOR QUESTION.

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0

Answer:

Graph A. not a function

Graph B. is a function

Mapping A. is a function

Mapping B. not a function

Table A. not a function

Table B. is a function

Sunny_sXe [5.5K]3 years ago
3 0

Answer:

a graph. not a function

b graph.function

a table. not a function

b table. function

maaping a. function

mapping b. not a function

Step-by-step explanatio n:

mark me brainelst plz

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Use the distributive property to create an equivalent expression to 7(2j + 3 + 2j).
Scorpion4ik [409]

Answer:

28j + 21

Step-by-step explanation:

combine like terms

7(2j+ 3+ 2j)

7(4j+3)

Distribute

7(4j + 3)

=

28j + 21

6 0
3 years ago
Read 2 more answers
The functions f (theta) and g (theta) are sine functions, where f (0) equals g (0) equals 0.The amplitude of f (theta) is twice
777dan777 [17]
If period of f(\theta) is one-half the period of g(\theta) and
<span>g(\theta)  has a period of 2π, then T_{g} =2T_{f}=2 \pi and T_{f}= \pi.
</span>
To find the period of sine function f(\theta)=asin(b\theta+c) we use the rule T_{f}= \frac{2\pi}{b}.
<span /><span />
f is sine function where f (0)=0, then c=0; with period \pi, then f(\theta)=asin 2\theta, because T_{f}= \frac{2 \pi }{2} = \pi. 

To find a we consider the condition f( \frac{ \pi }{4} )=4, from where asin2* \frac{\pi}{4} =a*sin \frac{ \pi }{2} =a=4.

If the amplitude of f(\theta) is twice the amplitude of g(\theta) , then g(\theta) has a product factor twice smaller than f(\theta) and while period of g(\theta)<span> </span> is 2π and g(0)=0, we can write g(\theta)=2sin\theta.






8 0
3 years ago
Factor 4x12−25y6<br><br> .<br><br> Enter your answer in the box.
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I got 256 as the answer
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Answer:

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