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tiny-mole [99]
3 years ago
14

Simplify the following cube root: cube root( 54x^6)

Mathematics
2 answers:
Mamont248 [21]3 years ago
5 0
9x^1 is the answer I believe
vlabodo [156]3 years ago
4 0

Answer:

3x²·\sqrt[3]{2}

Step-by-step explanation:

∛54x^6 = √(3)³ · 2 · x³ · x³  =  3x²· ∛2

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What is 3 1/2 plus 2 1/7
ololo11 [35]
3+2+1/2+1/7
5+1/2+1/7
5+7/14+2/14
5+9/14
5 9/14
5 0
3 years ago
Read 2 more answers
The radius of a cylindrical construction pipe is 1.5ft. If the pipe is 18ft long, what is its volume? Use the value 3.14 for π ,
olya-2409 [2.1K]
\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=1.5\\
h=18
\end{cases}\implies V=\pi \cdot 1.5^2\cdot 18
3 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Troyanec [42]

Answer: 300

Step-by-step explanation:

Let the number be represented by x.

Therefore, based on the information given in the question, this can be expressed as:

36% of x = 108

36/100 × x = 108

0.36 × x = 108

0.36x = 108

x = 108/0.36

x = 300

Therefore, the number is 300

8 0
3 years ago
Find the value of x for which p is parallel to q, if m∠1 = (9x) and m∠3 = 117.
kvasek [131]
If p||q then, m∠1=m∠3

9x = 117
x = 117/9
x = 13 
5 0
3 years ago
Read 2 more answers
There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
2 years ago
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