I’m not sure if this helps, but the area of a hexagon with a perimeter of 12 inches would be 10.39 inches squared
January . . . $57.85
March . . . . 4 times as much = 4 (57.85) = $231.40
Deposit 78.45 more . . . ($231.40 + 78.45) = <em>$309.85</em> .
Notice that "interest" is never mentioned anywhere in this problem.
In other words, it doesn't matter whether Julie's savings account is
in a bucket in the basement, a mayonnaise jar on the porch, under
her mattress, or in a bank that pays no interest.
Without interest, $309.85 is what she <em><u>does</u></em> have<em><u /></em> in November, which
is about right for savings accounts in banks these days.
What her balance <em><u>should</u></em> be in November is an entirely different subject.
Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
For this case, the first thing we must do is define a variable.
We have then:
n: number of days.
We now write the explicit formula that represents the problem.
We have then:
an = 4n + 15
Where,
15: crunches the first day
4: increase the number 4 each day
Answer:
An explicit formula for the number of crunches Abbie will do on day n is:
an = 4n + 15
X = adults
Y = child
X+y=168
X=168-y
$10x + $7y = $1446
10(168-y) + 7y = 1446
1680 - 10y + 7y = 1446
-3 y = -234
Y = 78
X = 168-78
X = 90
$10*90 + $7*78 =
$900 + $546 = $1446