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madam [21]
3 years ago
5

Domain of the function

Mathematics
1 answer:
Umnica [9.8K]3 years ago
6 0
F(x) = ln (6-x); find the domain.

The domain of the "ln" function is (0, infinity), or "x is greater than zero."

Thus, the domain of the given function is  "(6-x) is greater than zero."

Solve this:  6-x > 0.  Add x to both sides.  Then 6 > x, or x < 6 (answer)
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The roots of a quadratic function are x = -3 and x = 2/3. Which of the following would be the constant term of the equation in s
Alla [95]

Answer:

-2

Step-by-step explanation:

Since the roots are known and the function is a quadratic function, we can write down the function:

y = (x+3)(x-2/3) since when the roots are plugged in, the function gives 0.

Standard form means that the function has to be expanded:

y = (x+3)(x-2/3) = x^{2}+3x - 2x/3 - 3*2/3

y = x^{2}+ 7x/3 - 2

The constant term is -2.

7 0
3 years ago
In the diagram below of right triangle JTM, JT = 12, JM= 6, and m_JMT = 90.
olganol [36]

Answer:

√3/3

Step-by-step explanation:

8 0
3 years ago
Pls help me just drop the answer below I need help fast
Phoenix [80]

Answer:

i believe the answer is 0,2

7 0
3 years ago
Read 2 more answers
If a circle has an area of 84π units then what is the measure of its
Tatiana [17]
  • <em>Answer:</em>

<em>a. 2√21 units</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<u><em>Area formula</em></u>

<em>A = π·r²</em>

  • <em>replace A</em>

<em>84π = πr²</em>

<em>r² = 84π/π</em>

<em>r² = 84</em>

<em>r² = 2²×3×7</em>

<em>r = √2²×3×7</em>

<em>r = 2√3×7</em>

<em>r = 2√21</em>

<em>Good luck !</em>

6 0
3 years ago
Sin(cos^-1 x)<br><br> how to solve?
tatiyna

Answer:

sin(cos^{-1}x)=\sqrt{1-x^2}

Step-by-step explanation:

let us assume

cos^{-1} x=\theta\\x=cos\theta\\

now

sin(cos^{-1}x) can be written as sin\theta

we know  sin^2\theta+cos^2\theta=1

so sin^2\theta=1-cos^2\theta

sin\theta=\sqrt{1-cos^2\theta}

now from above equation we can say that

sin\theta=\sqrt{1-x^2}

sin(cos^{-1}x)=\sqrt{1-x^2}

7 0
3 years ago
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