S=7 1/7 and t = 6 3/7. solve for s-t.
1 answer:
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Short answer: Radius of new circle = sqrt(6) * the original radius
Area = pi * r^2
A1 = 6*Area = pi * (k * r) ^2
A1 = 6*Area = k^2 * pi * r^2 Set up a proportion.
Proportion
Comment
The As Cancel, the pis cancel the r^2 cancel.
1/6 = 1 / k^2 Cross multiply
k^2 = 6 Take the square root of both sides.
sqrt(k^2) = sqrt(6)
k = sqrt(6)
Conclusion
The radius increases by a factor of sqrt(6) times.
Discussion. You may not like this method very much, but you will do a lot of it in Physics or Chemistry. You may prefer the second method.
Step One
Find the area of the original circle
Area = pi * r^2
r = 10.9
pi = 3.14
Area = pi * r^2
Area = 3.14 * 10.9^2
Area = 3.14 * 118.81
Area = 373.1
Step 2
Multiply this area by 6
Area1 = 6 * Area
Area1 = 6 * 373.1
Area1 = 2238.38
Step 3
Find the radius of the bigger circle
Area1 = 2238.38
pi = 3.14
r = ????
Area1 = pi * r^2
2238.38 = 3.14 * r^2 Divide both sides by 3.14
2238/3.14 = r^2
r^2 = 712.86 Take the square root of both sides.
sqrt(r^2) = sqrt(712.86)
r = 26.6994
Step 4
Divide by the original r
r/10.9 = 26.6994 / 10.9 = 2.44948
Here's where this get's a little messy. How do you know what to do with this. Perhaps just saying that the new radius = the original radius * 2.44958
But try taking the square root of 6 to see what happens.
sqrt(6) = 2.449489 is what you get, so the radius increases by sqrt(6) in size.
Comment
No matter which way you do this, it looks like a messy problem just because square root 6 is not easily recognized.
Area = pi * r^2
A1 = 6*Area = pi * (k * r) ^2
A1 = 6*Area = k^2 * pi * r^2 Set up a proportion.
Proportion
Comment
The As Cancel, the pis cancel the r^2 cancel.
1/6 = 1 / k^2 Cross multiply
k^2 = 6 Take the square root of both sides.
sqrt(k^2) = sqrt(6)
k = sqrt(6)
Conclusion
The radius increases by a factor of sqrt(6) times.
Discussion. You may not like this method very much, but you will do a lot of it in Physics or Chemistry. You may prefer the second method.
Step One
Find the area of the original circle
Area = pi * r^2
r = 10.9
pi = 3.14
Area = pi * r^2
Area = 3.14 * 10.9^2
Area = 3.14 * 118.81
Area = 373.1
Step 2
Multiply this area by 6
Area1 = 6 * Area
Area1 = 6 * 373.1
Area1 = 2238.38
Step 3
Find the radius of the bigger circle
Area1 = 2238.38
pi = 3.14
r = ????
Area1 = pi * r^2
2238.38 = 3.14 * r^2 Divide both sides by 3.14
2238/3.14 = r^2
r^2 = 712.86 Take the square root of both sides.
sqrt(r^2) = sqrt(712.86)
r = 26.6994
Step 4
Divide by the original r
r/10.9 = 26.6994 / 10.9 = 2.44948
Here's where this get's a little messy. How do you know what to do with this. Perhaps just saying that the new radius = the original radius * 2.44958
But try taking the square root of 6 to see what happens.
sqrt(6) = 2.449489 is what you get, so the radius increases by sqrt(6) in size.
Comment
No matter which way you do this, it looks like a messy problem just because square root 6 is not easily recognized.
Answer:
- 4
- -4
Step-by-step explanation:
When you follow the curve from the left toward x=2, you wind up at the open circle at (2, 4). The limit from that direction is 4.
When you follow the curve from the right toward x=2, you wind up at the open circle at (2, -4). The limit from that direction is -4.
Answer:
The coefficient of variation for the weight and age are 5.9% and 10.6%.
Step-by-step explanation:
The coefficient of variation (CV) is well defined as the ratio of the standard deviation to the mean. It exhibits the degree of variation in association to the mean of the population.
The formula to compute the coefficient of variation is:
Here σ = standard deviation and µ = mean.
Compute the mean and standard deviations of the two data set in Excel using the following functions.
Mean=AVERAGE()
Standard deviation=STDEV.S()
Consider the Excel sheet attached.
The mean and standard deviation of weight are:
Mean = 202, Standard deviation = 11.87
And the mean and standard deviation of weight are:
Mean = 25.88, Standard deviation = 2.75
Compute the coefficient of variation for the weight as follows:
Compute the coefficient of variation for the age as follows:
Thus, the coefficient of variation for the weight and age are 5.9% and 10.6%.
