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worty [1.4K]
3 years ago
6

What’s the angle of cda

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

∠ CDA = 32.3°

Step-by-step explanation:

See the given figure attached to this answer.

Draw perpendiculars from B and C on AD which is BE and CF.

Now, Δ ABE is a right triangle and AE² = AB² - BE² = 7.5² - 6² = 20.25

⇒ AE = 4.5 cm

Now, DF = AD - EF - AE = 24 - 10 - 4.5 = 9.5 cm {Since BC = EF}

And CF = BE = 6 cm.

Now, Δ CFD is a right triangle and  

\tan \beta  =\frac{CF}{FD} = \frac{6}{9.5}  = 0.6315 {Where β = ∠ CDA}

⇒ \beta  = \tan^{-1} (0.6315)=32.27 Degree.

So, ∠ CDA = 32.3° {Correct to one decimal place} (Answer)

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HELP!!! Anyone know how to solve I know the answer is (-3) but I don’t know how to get there. Thanks!!
Dima020 [189]

Answer:   v = -3

=========================================

Work Shown:

5 = \sqrt{-2-6v}+1\\\\5-1 = \sqrt{-2-6v}\\\\4 = \sqrt{-2-6v}\\\\4^2 = \left(\sqrt{-2-6v}\right)^2 \ \text{ .... square both sides}\\\\16 = -2-6v\\\\16+2 = -6v\\\\18 = -6v\\\\-6v = 18\\\\v = 18 \div (-6)\\\\v = -3

As you can see, we don't square both sides until the square root portion is fully isolated or on its own side. So it happens after we subtract 1 from both sides.

Technically, you are able to square both sides without first isolating the square root. But that would mean you'd have to use the FOIL rule and things would get a bit messier than they have to be. Not to mention that the square root term wouldn't fully go away (so you'd have to square again later down the line).

------------------

Checking the answer:

Replace every copy of v with -3. Simplify both sides. We should end up with the same number on each side

5 = \sqrt{-2-6v}+1\\\\5 = \sqrt{-2-6(-3)}+1\\\\5 = \sqrt{-2+18}+1\\\\5 = \sqrt{16}+1\\\\5 = 4+1\\\\5 = 5\\\\

The answer is confirmed.

4 0
3 years ago
The general form of the equation of a circle is x2+y2−4x−8y−5=0.
valentina_108 [34]

Answer:

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Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 4x - 8y - 5 = 0

Rearrange the x/y terms together and add 5 to both sides

x² - 4x + y² - 8y = 5

Use the method of completing the square on both the x/y terms

add ( half the coefficient of the x/y terms )² to both sides

x² + 2(- 2)x + 4 + y² + 2(- 4)y + 16 = 5 + 4 + 16

(x - 2)² + (y - 4)² = 25 ← in standard form

with centre (2, 4) and r = \sqrt{25} = 5

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