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3 years ago

Help plz :)) I would appreciate it

Mathematics

1 answer:

mart [117]3 years ago

8 0

Answer:

VW = 29

Step-by-step explanation:

Perimeter of the triangle = 82

Perimeter of the triangle = 4x + (x + 3) + (3x - 1)

4x + (x + 3) + (3x - 1) = 82

4x + x + 3 + 3x - 1 = 82

8x + 2 = 82

8x = 82 - 2

8x = 80

x = 10

VW = 3x - 1

VW = 3(10) - 1

VW = 30 - 1

VW = 29

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Which fraction is equivalent to 20%?

Rama09 [41]

Answer:

1/5

Step-by-step explanation:

1= 100%

1/5= 100%/5

1/5= 20%

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A survey of the 12th grade students at Gaffigan High School found that 84% of the seniors have their driver’s licenses, 16% of s

Anna35 [415]

Use the formula for the conditional probability:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr B}.$

Consider such events

A - a senior takes the bus to school every day;

B - a senior has a driver’s license,

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$Pr(A\cap B)=0.14$ ,

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and

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3 years ago

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What statement is valid….

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3 0

2 years ago

Please help i put 15 points for this

PilotLPTM [1.2K]

Answer:

Options 3, 4 and 5

Step-by-step explanation:

Given:

F(x) = x³ + 3x² - 25x - 75

Factor the given function:

F(x) = x³ + 3x² - 25x - 75

⇒ take x² a common from (x³ + 3x²) and (-25) a common from (- 25x - 75)

F(x) = x²(x+3) - 25 (x+3)

⇒ take (x+3) as a common

F(x) = (x+3) (x² - 25)

(x² - 25) = (x-5) (x+5)

∴ F(x) = (x+3) (x-5) (x+5)

The answer are options 3, 4 and 5

7 0

4 years ago

Researchers wondered if there was a difference between males and females in regard to some common annoyances. They asked a rando

inysia [295]

Answer:

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

D) The data come from a Population that is Normally distributed

F) the samples are independent

c)

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Step-by-step explanation:

Given data Among the 530 males surveyed, 175 responded "Yes

The sample proportion of males

$p_{m} ^{-} = \frac{x}{n} = \frac{175}{530} = 0.3301$

The sample proportion of 575 Females surveyed, 218 responded "Yes

$p_{fem} ^{-} = \frac{x}{n} = \frac{218}{575} = 0.3791$

The proportions of the females and males who took the survey who are annoyed by the behavior in question are 0.3301 and_0.3791 respectively

The data come from a Population that is normally distributed.

The two samples are independent

Null hypothesis: H₀: $p_{m} ^{-} - p^{-} _{fm} \geq 0$

Alternative Hypothesis H₁: $p_{m} ^{-} - p^{-} _{fm} \leq 0$

We will use two samples Z - hypothesis test

$Z = \frac{p^{-} _{m} - p^{-} _{fem} }{se(p^{-} _{m}-p^{-} _{fem} ) }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{p_{m}(1-p_{m}) }{n_{m} }+\frac{p_{fem} (1-p_{fem} )}{n_{fem} } }$

$Se(p_{m} -p_{fem}) = \sqrt{\frac{0.3301(1-0.3301) }{530 }+\frac{0.3791(1-0.3791)}{575} }$

$Se(p_{m} ^{-} - p^{-} _{fem} ) = \sqrt{0.000826} = 0.0287$

The test statistic

$Z = \frac{0.3301-0.3791}{0.02875}$

Z = -1.7043

|Z| = |-1.7043|

The tabulated value Z₀.₉₅ = 1.96

The calculated Z= 1.7043 < 1.96 at 0.05 level of significance

The null hypothesis is accepted

Conclusion:-

The evidence suggest not a higher proportion of females are annoyed by this behavior

4 0

3 years ago