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Sergio039 [100]
2 years ago
15

Given the points a(0, 0), B(e, f), c(0, e) and D(f, o), determine if line segments AB and CD are parallel, perpendicular or

Mathematics
1 answer:
Nitella [24]2 years ago
4 0
Perpendicular
Bit confusing but that should be right
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F(x)=20/4+3e−0.2x
sdas [7]

Answer:

12.6

Step-by-step explanation:

Given the function, F(x)=20/4+3e−0.2x

Where e is an exponential function,

To get f(3), we need to substitute x = 3 into the given function

F(3) = 20/4 + 3e - 0.2(3)

f(3) = 5 + 3e - 0.6

f(3) = 4.4+3e

Substituting the value of e = 2.718

f(3) = 4.4+3(2.718)

f(3) = 12.554

f(3) = 12.6 to the nearest tenth.

8 0
3 years ago
Given the following exponential function, identify whether the change represents
siniylev [52]

Hello there!

Using the given exponential function of y = 64(0.97)^x, we can tell that it is a decaying exponential function since the rate is less than 1.

The percent of decrease is 3% since 97% of the value is retained per x time.

8 0
3 years ago
Joshua and his four friends have 1/2 pakage of a crackers. How many pakages of crackers do they have in all
maks197457 [2]

answer:

2.5 or 2 1/2

work:

4(joshuas friends)+1(joshua)=5

5×1/2=5/2

5/2= 2.5

7 0
3 years ago
How u can convert decimal to a fraction in .23?
Vlada [557]

23

%

=

23

100

=

0.23

First we have to think that the symbol

%

=

1

100

so that

23

%

=

23

⋅

(

1

100

)

this is read twenty three percent is equal to twenty three multiplied by one divided by one hundred.

the result is the fraction

23

100

Now, to convert to decimal, simply divide 23 by 100

23

÷

10

=

2.3


and

2.3

÷

10

=

0.23

this is the same as

23

÷

100

=

0.23

4 0
3 years ago
For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

f(x) = x^2;\ k (x) = x ^ 2 -7

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

3 0
3 years ago
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