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dezoksy [38]
3 years ago
12

Simplify: 3r+n²-r+5-2n+2

Mathematics
2 answers:
lutik1710 [3]3 years ago
7 0
3r+n2−r+5−2n+2<span />=3r+n2+−r+5+−2n+2=3r+n2+−r+5+−2n+2<span />=(n2)+(−2n)+(3r+−r)+(5+2)<span />=n2+−2n+2r+7<span /><span />
=n2−2n+2r+7
nikitadnepr [17]3 years ago
4 0
3n+n^2-r+5-2n+2
5+2=7
3n+2n=5n
n^2 -r +5n +7
((IDK what order the variables are suppose to go in put i think I got it in the right order.))
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What is the equation when y=5x+4 is reflected over the x-axis, y-axis &amp; y=x?
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A) y=-5x-4

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So we have the equation:

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Let's write this in function notation. Thus:

y=f(x)=5x+4

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To flip a function over the x-axis, multiply the function by -1. Thus:

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f(x)=5x+4

Switch:

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