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Margaret [11]
3 years ago
9

A rectangular field is 90 yards long and 60 yards wide.Give the length and width of another rectangular field that has the same

perimeter but a larger area.
Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

The length and width of another rectangular field with same perimeter but a larger area is 80 m by 70 m

Step-by-step explanation:

The perimeter of the existing field is

2(l + b)

= 2(90 + 60) = 2(150) = 300 yards

So we want another field having the same perimeter but a larger area

The area we have here is 90 * 60 = 5,400 square yards

If we had 80 by 70

Perimeter will still be 2(70 + 80) = 150

But the area will be 80 * 70 = 5,600 square yards

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40 points answer ASAP
suter [353]

Answer: See below

Step-by-step explanation:

a) There is a correlation between the number of employees in the plant and the number of products produced yearly. Specifically, a positive correlation exists because, as we can see on the table, as the number of employees increases, the number of products also increases. And the rate of increase is constant.

b) Let the function be: y = mx + b

When x = 0; y = 120

So:

120 = 0 + c

c = 120

Now the slope:

\text { Slope }=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{200-120}{10-0}=\frac{80}{10}=8

Therefore, the equation that best fits the data is y = 8x + 120

c) The slope in the function represents the constant rate of change, meaning that as the number of employees increases by 1, the number of products produced monthly increases by 20. While the y-intercept of the plot, which is 120, indicates the constant number of products, that is to say, when there are no employees, there are still 120 products.

8 0
2 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
1.6÷_=4 a deciaml division promblem what is the missing divisor
Sladkaya [172]

1.6 divided by x =4

we can exchange the 4 and the x

1.6 divided by 4 =x

.4 =x

8 0
3 years ago
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5x-6_&lt; -5x +16 <br> solve
Olegator [25]

Answer:

haha

Step-by-step explanation:

thanks for the points

4 0
3 years ago
The fraction a/b must be equal to which expression
OlgaM077 [116]

Answer:

q

Step-by-step explanation:

3 0
3 years ago
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