3 years ago

Help solving this acceleration problem.

Mathematics

1 answer:

Misha Larkins [42]3 years ago

8 0

Answer:

168.4953 (m/s)

Step-by-step explanation:

a(t)=x''(t)=(0.0951t⁴-0.101t³+0.837t²+3.87t-9.37)''= =4*3*0.951t²-3*2*0.101t+2*0.837 =11.412t²-0.606t+1.674.

a(3.85)=11.412*3.85²-0.606*3.85+1.674=168.4953

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What is 0.002 one tenth of.

jeka94

Let's say is "x".

so, "x" is the whole or 10/10 whilst 0.002 is 1/10 then, let's check

$\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
0.002&\frac{1}{10}\\\\
x&\frac{10}{10}
\end{array}\implies \cfrac{0.002}{x}=\cfrac{\frac{1}{10}}{\frac{10}{10}}\implies \cfrac{0.002}{x}=\cfrac{\frac{1}{10}}{1}
\\\\\\
\cfrac{0.002}{x}=\cfrac{1}{10}\implies \cfrac{0.002\cdot 10}{1}=x$

7 0

3 years ago

An article in the Journal of Aircraft described a new equivalent plate analysis method formulation that is capable of modeling a

mezya [45]

Answer:

Given:

n = 15

c = 95% = 0.95

Let us assume:

α = 0.05

Determine the difference in value of each pair.

→See attached for the table←