Help solving this acceleration problem.
1 answer:
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Answer:
Step-by-step explanation:
Figure 1,
EA and EB are the opposite rays.
EC bisects angle FEG.
a). m∠FEC =
(2x + 6) =
2x + 6 = 20
2x = 14
x = 7
b). ED⊥AB
Therefore, m∠AED = 90°
m∠AED = 11y + 13 = 90°
11y = 90 - 13
11y = 77
y = 7
Figure 2,
NC bisects ∠WNB,
Therefore, ∠WNC ≅ ∠CNB
m∠WNC = m∠CNB
3v - 4 = 2v + 6
3v - 2v = 4 + 6
v = 10
Therefore, m∠WNC = x = (3v - 4)
x = 3(10) - 10
= 30 - 10
x = 20