The awnsser is 9..................
So here are the answers to the given questions above:
1. Since the equation is already given, what we are going to do is to solve for x first.
<span>x + (2x – 10) + 1/2 (2x – 10) = 145
x + (2x -10) + x - 5 = 145
x + 2x + x - 10 - 5 = 145
4x = 145 +10 + 5
4x = 160 <<divide both sides by 4 and we get
x = 40.
Therefore, the amount of white paint is 40ml.
The amount of blue paint is 70ml and the green paint is 35ml.
So the difference between the a</span><span>mounts of white paint and blue paint Vivian combined is 30ml.
2. T</span>he equation of the line that passes through the points (-2, 1) and (1, 10) would be: <span>3x - y = -7, the last option. In order to check, just plug in the given ordered pairs.</span>
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
Answer:
Step-by-step explanation:
From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (
) and are parallel to 
The parallel vector to the line i + zj+k = ai + bj + ck
Hence, the equation for the line is :
x = 4 + t
y = -5 + 2t
z = 2 + t
Thus, x, y, z = ( 4+t, -5+2t, 2+t )
The symmetric equation can now be as follows:
∴
