Answer:
The swimmer must move in the direction 338.2°
Step-by-step explanation:
Since the river flows due south at 1.2 miles per hour and the swimmer swims 3 miles per hour due east of the river, since their directions are perpendicular, the resultant speed is the hypotenuse of the triangle formed by the two perpendicular directions.
The direction of the resultant speed is thus θ = tan⁻¹( vertical component/horizontal component) where vertical component = 1.2 mph due south = -1.2 mph and horizontal component = 3 mph due east = + 3 mph
So, θ = tan⁻¹(-1.2 mph/+ 3mph)
θ = tan⁻¹(-1.2/3)
θ = tan⁻¹(-0.4)
θ = -21.8°
θ = -21.8° + 360° (since we are in the fourth quadrant- between east and south)
θ = 338.2°
So, <u>the swimmer must move in the direction 338.2°</u>.
Answer:
The answer is b=18/z
Step-by-step explanation:
Let's solve for b.
bz/2=9
Step 1: Divide both sides by z/2.
1/2bz/z/2=9/z/2
b=18/z
Answer:
b=18/z
Answer:
110:8.6
Step-by-step explanation:
110/1:68.8/5
=110:8.6
6 as a fraction is 6/1
12/2
18/3
24/4
