<h3>Answer:</h3>
(x, y) ≈ (1.49021612010, 1.22074408461)
<h3>Explanation:</h3>
This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.
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Setting the y-values equal and squaring both sides of the equation gives ...
... √x = x² -1
... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides
... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.
By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.
Answer:
1. 10^(38)
2. total amount = 10^11 or total amount = $100000000000
Step-by-step explanation:
For every time that we multiply powers with the same base we maintain the base and sum the powers. Therefore we have:
1. (10^32)*(10^6)
10^(32 + 6)
10^(38)
2. If each of the 10^6 programmers make 10^5 then the total money they make together is the product of the number of programs with the sallary each makes. We have:
total = (10^6)*(10^5)
total = 10^(6 + 5)
total = 10^11
total = $100000000000
Answer:
T.A. = 16√3 units²
Step-by-step explanation:
∵ The total area = the area of the four faces
∵ The four faces are equilateral triangles with side length 4
∵ Area of the equilateral Δ = 1/4 s² √3
∴ T.A. = 4 × 1/4 × 4² × √3 = 16√3 units²
Answer:
Point C
Step-by-step explanation:
We want to reflect across the x axis
That means the y coordinate changes sign
Z = ( 5 1/2 , 3)
Z' = ( 5 1/2 , -3)
That is point C
Step-by-step explanation:
In order to find the length of side TS, first we need to find the length of side TR which is perpendicular to side QS.
By Geometric mean property:
