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ryzh [129]
3 years ago
14

Actividad: Elabora tu propia ficha de autoevaluación de las 11 áreas que desarrollas y contesta las siguientes preguntas:

Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0

Answer:

i dont speak chinese

Step-by-step explanation:

sorry ;-;

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What is 67.142 rounded to the nearest ones?
Nezavi [6.7K]
67.142 rounded to the nearest ones is 67 cause the .1 is not .5 or greater.
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Find the next item in the pattern 9,18,26,33
KATRIN_1 [288]

Answer:

39

Step-by-step explanation:

you are going down like 9,8,7,6 i think

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Which of the following choices is the simple formula for the nth term of the following arithmetic sequence?
kkurt [141]
\bf 7~~,~~\stackrel{7-4}{3}~~,~~\stackrel{3-4}{-1}~~,~~\stackrel{-1-4}{-5}~~,~~\stackrel{-5-4}{-9}~~,~~...

so namely, the "common difference" d = -4, and the first term a₁ = 7.

\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
d=-4\\
a_1=7
\end{cases}
\\\\\\
a_n=7+(n-1)(-4)\implies a_n=7+(4-4n)
\\\\\\
a_n=11-4n\implies a_n=-4n+11
8 0
3 years ago
Carly stated, "All pairs of rectangles are dilations. " Which pair of rectangles would prove that Carly’s statement is incorrect
xenn [34]

The pair of rectangle that will prove Carly's statement incorrect is: Option 3: A rectangle with length 4 and width 3. A rectangle with length 3 and width 2.

<h3>How to find if a pair of figure is not dilated version of each other?</h3>

Dilation of a figure will leave its sides get scaled (multiplied) by same number.

Thus, suppose if a rectangle is dilated, and its sides were of length = L and width = W, then its dilated version would be having length = Ln, and width = Wn where n is the factor of scaling.

Thus, we get:

n = \dfrac{Ln}{L} = \dfrac{Wn}{W}\\\\or\\\\\text{Ratios of corresponding dilated sides are equal}

For the given cases, checking all the given pairs:

  • Case 1:  A rectangle with length 4 and width 2. A rectangle with length 8 and width 4.

Getting length to length and width to width ratio:

\dfrac{L_1}{L_2} = \dfrac{4}{8} = \dfrac{1}{2}\\\\\dfrac{W_1}{W_2} = \dfrac{2}{4} = \dfrac{1}{2}\\\\\\Thus, \dfrac{L_1}{L_2} = \dfrac{W_1}{W_2}

Pair given are dilated version of each other.

  • Case 2:  A rectangle with length 4 and width 2. A rectangle with length 6 and width 3.

Getting length to length and width to width ratio:

\dfrac{L_1}{L_2} = \dfrac{4}{6} = \dfrac{2}{3}\\\\\dfrac{W_1}{W_2} = \dfrac{2}{3} \\\\\\Thus, \dfrac{L_1}{L_2} = \dfrac{W_1}{W_2}

Pair given are dilated version of each other.

  • Case 3:  A rectangle with length 4 and width 3. A rectangle with length 3 and width 2.

Getting length to length and width to width ratio:

\dfrac{L_1}{L_2} = \dfrac{4}{3}\\\\\dfrac{W_1}{W_2} = \dfrac{3}{2} \\\\\\Thus, \dfrac{L_1}{L_2} \neq  \dfrac{W_1}{W_2}

Pair given are not dilated version of each other.

  • Case 4:  A rectangle with length 4 and width 3. A rectangle with length 2 and width 1.5.

Getting length to length and width to width ratio:

\dfrac{L_1}{L_2} = \dfrac{4}{2} = \dfrac{2}{1}\\\\\dfrac{W_1}{W_2} = \dfrac{3}{1.5} = \dfrac{2}{1}\\\\\\Thus, \dfrac{L_1}{L_2} = \dfrac{W_1}{W_2}

Pair given are dilated version of each other.

Thus, the pair of rectangle that will prove Carly's statement incorrect is: Option 3: A rectangle with length 4 and width 3. A rectangle with length 3 and width 2.

Learn more about dilation here:

brainly.com/question/3266920

5 0
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