You have two 30-60-90 triangles, ADC and BDC.
The ratio of the lengths of the sides of a 30-60-90 triangle is
short leg : long leg : hypotenuse
1 : sqrt(3) : 2
Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC
First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30
Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10
AB = AC - BC = 30 - 10 = 20
Answer:
24mm
Step-by-step explanation:
since it's a similar triangle, we solve;
EH/EG=DH/DG
EH=56mm;
EG=44.8mm;
DH=35mm;
DG=X+4.
Fix them,
56/44.8=35/x+4
cross multiply
56(x+4)=35×44.8
56x+224=1,568
collect the like term
56x=1,344
divide via by 56
56x/56=1344/56
x=24mm
Check/ verify
EH/EG=DH/DG
56/44.8=35/24+4
56/44.8=35/28
CROSS MULTIPLY OVER THE EQUAL SIGN.
56×28=35×44.8
1,568=1,568
THAT'S CORRECT.
Answer:
Step-by-step explanation:
Remark
The slope intercept line is written as y = mx + b in it's general form.
You can get the slope, m, immediately because it is given as -2
So far what you have is y = -2x + b
y intercept
To get the y intercept, use the point (-3 , 4)
x = - 3
y = 4
4 = -2*(-3) + b
4 = 6 + b Subtract 6 from both sides
4 - 6 = 6-6 + b
b = - 2
Line
y = -2x - 2
(a,8)
y = -2a - 2
8 = -2a - 2 Add 2 to both sides
8 +2 = -2a -2+2 Combine
10 = - 2a Divide by - 2
10/-2 = a
a = -5
(5,b)
y = -2x - 2
x = 5
y = b
b = -2*5 - 2
b = -10 - 2
b = - 12
Given:
Total forest area = 43,000
Old growth trees forest = 0.2%
To find:
The area of the old growth trees.
Solution:
We have,
Total forest area = 43,000
Old growth trees forest = 0.2%
Area of the old growth trees = 0.2% of 43,000
= 
= 
Therefore, the area of the old growth trees is 86 acres.
