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3 years ago

Which number, when substituted for x, make the equation 4x+ 8= 16 true

Mathematics

2 answers:

kotegsom [21]3 years ago

7 0

Answer:

x=2

Step-by-step explanation:

ok so this is just a substitution problem.

we need to get the variable (x) by itself on one side.

4x+8=16. so, lets remove 8 from the left side, and whatever we do to one side also has to happen to the other.

4x+8=16

-8 -8

4x=8. So now, we want to get 4 separate from x, and the only thing we can do is divide.

4x=8

/4 /4

x=2. there you have it, x is 2.

Levart [38]3 years ago

5 0

Answer:

X=2

Step-by-step explanation:

4x+8=16

4x=8

x=2

4(2)+8=16

8+8=16

16=16

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7 0

3 years ago

Range for 27,22,26,28,30,27,29

Allisa [31]

The range is a statistical property that consists in the difference between the smaller number and the bigger number of a sequence.

30 - 22 = 8

Hope it helped!

4 0

4 years ago

What is the answer ，and how do you solve it .please help

xz_007 [3.2K]

Answer:

Step-by-step explanation:

2000/ 2x = 10

Multiply each side by 2x

2000/ 2x = 10 *2x

2000 = 20x

Divide by 20

2000/20 = 20x/20

100 = x

Take the square root of each side

sqrt(100) = sqrt(x)

10 = sqrt(x)

5 0

3 years ago

A rectangular prism with a volume of 4 cubic units is filled with cubes with side lengths of 1/3 unit. How many 1/3 unit cubes d

Ghella [55]

Answer:

108 cubic units

Step-by-step explanation:

V = 4 cubic units

v = (1/3)³ = 1/27 cubic units

V/v = 4/(1/27) = 4/1 x 27/1 = 108 cubic units

5 0

4 years ago

Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule

-BARSIC- [3]

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = scores of an IQ test

SO, X ~ Normal( $\mu=100, \sigma^{2} = 17^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, the empirical rule states that;

68% of the data values lie within 1 standard deviation from the mean.

95% of the data values lie within 2 standard deviations from the mean.

99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

z score for 66 = $\frac{X-\mu}{\sigma}$ = $\frac{66-100}{17}$ = -2

z score for 134 = $\frac{X-\mu}{\sigma}$ = $\frac{134-100}{17}$ = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

z score for 83 = $\frac{X-\mu}{\sigma}$ = $\frac{83-100}{17}$ = -1

z score for 117 = $\frac{X-\mu}{\sigma}$ = $\frac{117-100}{17}$ = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117 = $\frac{32\%}{2}$ = 16%.

8 0

3 years ago