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lana [24]
2 years ago
11

="TexFormula1" title="x^{2} +y^{2}\leq 1\\y-x^{2}\ \textgreater \ 0" alt="x^{2} +y^{2}\leq 1\\y-x^{2}\ \textgreater \ 0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ilya [14]2 years ago
7 0

Answer:

hi how are you

good afternoon

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Calc 3 iiiiiiiiiiiiiiiiiiiiiiiiiiii
Lilit [14]

Take the Laplace transform of both sides:

L[y'' - 4y' + 8y] = L[δ(t - 1)]

I'll denote the Laplace transform of y = y(t) by Y = Y(s). Solve for Y :

(s²Y - s y(0) - y'(0)) - 4 (sY - y(0)) + 8Y = exp(-s) L[δ(t)]

s²Y - 4sY + 8Y = exp(-s)

(s² - 4s + 8) Y = exp(-s)

Y = exp(-s) / (s² - 4s + 8)

and complete the square in the denominator,

Y = exp(-s) / ((s - 2)^2 + 4)

Recall that

L⁻¹[F(s - c)] = exp(ct) f(t)

In order to apply this property, we multiply Y by exp(2)/exp(2), so that

Y = exp(-2) • exp(-s) exp(2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-s + 2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-(s - 2)) / ((s - 2)² + 4)

Then taking the inverse transform, we have

L⁻¹[Y] = exp(-2) L⁻¹[exp(-(s - 2)) / ((s - 2)² + 4)]

L⁻¹[Y] = exp(-2) exp(2t) L⁻¹[exp(-s) / (s² + 4)]

L⁻¹[Y] = exp(2t - 2) L⁻¹[exp(-s) / (s² + 4)]

Next, we recall another property,

L⁻¹[exp(-cs) F(s)] = u(t - c) f(t - c)

where F is the Laplace transform of f, and u(t) is the unit step function

u(t) = \begin{cases}1 & \text{if }t \ge 0 \\ 0 & \text{if }t < 0\end{cases}

To apply this property, we first identify c = 1 and F(s) = 1/(s² + 4), whose inverse transform is

L⁻¹[F(s)] = 1/2 L⁻¹[2/(s² + 2²)] = 1/2 sin(2t)

Then we find

L⁻¹[Y] = exp(2t - 2) u(t - 1) • 1/2 sin(2 (t - 1))

and so we end up with

y = 1/2 exp(2t - 2) u(t - 1) sin(2t - 2)

7 0
2 years ago
Which expressions are equivalent when m = 1 and m = 4?
s344n2d4d5 [400]

Answer:

expression 2

Step-by-step explanation:

<h2><u>Which expressions are equivalent when m = 1 and m = 4?</u></h2>

<h3><u>first expression:</u></h3>

5m -3 and 2m + 5 + m

when m = 1

5(1) - 3 = 2  and 2(1) + 5 + 1 = 8

and m = 4

5(4) -3 =23 and  2(4) + 5 + 4 = 17

<u>expression 1 IS</u><u> NOT EQUIVALENT</u><u> </u>

<h3><u>second expression  :</u></h3>

3 m + 4 and m + 4 + 2 m

when m = 1

3 (1) + 4 = 7 and 1 + 4 +2 (1) = 7

and m = 4

3 (4) + 4 = 16 and 4 + 4 +2 (4) = 16

expression 2 <u>IS  EQUIVALENT </u>

<h3><u>third expression :</u></h3>

2 m + 7 and 3 m - 3 + m

when m = 1

2(1) + 7 = 9 and 3(1) -3 + 1 = 1

and m = 4

2(4) + 7 = 15  and 3(4) -3 + 4 = 13

expression 3 IS <u>NOT EQUIVALENT</u>

<h3><u>fourth expression :</u></h3>

5 m + 3 and 4 m + 2 + 2 m

when m = 1

5(1)+ 3 = 8  and 4(1) + 2 +2(1) = 8

and m = 4

5(4)+ 3 = 23  and 4(4) + 2 +2(4) = 26

expression 4 is <u>NOT EQUIVALENT </u>

the expression that is <u><em>EXPRESSION 2 </em></u>

8 0
3 years ago
Read 2 more answers
Use what you have learned to solve the following polynomial equation by either completing the square or using the quadratic form
USPshnik [31]
<span>(x^2-4x-6) factors into:</span>
(x -5.1623)     (x+1.1623)
Therefore x = 5.1623 and      x = -1.1623

(4x^2-8x-2) <span>factors into:
(x -2.2247)  *  (x +2.2474)
</span>
Therefore x = 2.2247   and x=  -0.22474


7 0
3 years ago
I need help to Find the value of x. Round to<br> the nearest tenth.
Charra [1.4K]

Answer:

4.5

Step-by-step explanation:

We are given opposite and adjacent, so use tangent

tan(37)=x/6

6tan(37)=4.521324301

7 0
2 years ago
What percentage of students age 15 and above travel to school by car? Round to the nearest whole percent.
Juli2301 [7.4K]

Answer:

hey, do u go to flvs?

Step-by-step explanation:

5 0
2 years ago
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