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lana [24]
2 years ago
11

="TexFormula1" title="x^{2} +y^{2}\leq 1\\y-x^{2}\ \textgreater \ 0" alt="x^{2} +y^{2}\leq 1\\y-x^{2}\ \textgreater \ 0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Ilya [14]2 years ago
7 0

Answer:

hi how are you

good afternoon

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see explanation

Step-by-step explanation:

differentiate using the power rule.

\frac{d}{dx}( ax^{n} ) = nax^{n-1} , thus

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x = 5 → 2(5) - 1 = 10 - 1 = 9

To find the value of x for minimum , equate \frac{d}{dx} to zero

2x - 1 = 0 , then

2x = 1 and

x = \frac{1}{2}

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