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Anvisha [2.4K]
3 years ago
6

Factor the expression.

Mathematics
2 answers:
Kamila [148]3 years ago
7 0

Answer:

5(5k²+6)(4k-3)

Step-by-step explanation:

100k³ - 75k² + 120k - 90

Take 5 common above:

= 5(20k³ - 15k² + 24k - 18) ------- eq1

First let simplify 20k³ - 15k² + 24k - 18

= (20k³ - 15k²) + (24k - 18) ---------eq2

Factor out 6 from 24k - 18 :

6(4k-3)

Factor out 5k² from (20k³ - 15k²):

5k²(4k -3)

eq2 becomes:   = 6(4k-3) + 5k²(4k -3)

Factor out common term 4k-3

(6+ 5k²)(4k -3) or (5k²+6)(4k-3)

Thus eq1 becomes:

5(5k²+6)(4k -3)

vova2212 [387]3 years ago
4 0

Answer:

The correct answer is Option 1. 5(5k² + 6)(4k - 3)

Step-by-step explanation:

The given expression is,

100k³ - 75k² + 120k - 90

<u>Factor the expression</u>

100k³ - 75k² + 120k - 90

= 5[20k³ - 15k² + 24k - 18]   [Taking 5 as common factor]

= 5[ 5k²(4k - 3) + 6(4k - 3) ]

= 5[(4k - 3)(5k² + 6)]

= 5[(5k² + 6) (4k - 3)]

Therefore the correct answer is Option 1. 5(5k² + 6)(4k - 3)

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What is the midpoint between (3, -1) and (7, -5)?<br> Group of answer choices
Hatshy [7]

Answer:

The answer is

<h2>( 5 , - 3)</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

<h3>M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )</h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3, -1) and (7, -5)

The midpoint is

M = ( \frac{3 + 7}{2}  , \:  \frac{ - 1 - 5}{2} ) \\  = ( \frac{10}{2}  \: , \:  -  \frac{6}{2} )

We have the final answer as

<h3>( 5 , - 3)</h3>

Hope this helps you

6 0
3 years ago
Can someone help me with this
Jobisdone [24]
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X^2-7x-6=0<br> Use the quadratic formula to complete the equation show step by step
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3 years ago
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In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. if there were 45 basket
IgorLugansk [536]
Let
 x: number of regular basketball
 y: number of long-distance basket
 We have the following system of equations:
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 y = 45-x
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3 years ago
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