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s2008m [1.1K]
3 years ago
6

HELP ANSWER GETS BRANLIEST ANSWER!

Mathematics
1 answer:
AleksAgata [21]3 years ago
3 0

Answer: -5/4

Step-by-step explanation: You can use the graph to count the slope. The change in y is -5 and the change in x is 4, and slope is change in y over change in x.

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Suppose your restaurant bill comes to $28.35 .Find your total cost if the tax is 6.25% and you leave a 20% tip on the amount bef
Anon25 [30]
Your total after tax is $30.12
A 20% tip is approximately $5.50 ($5.67)
3 0
4 years ago
1: Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not hav
OLga [1]

Answer:

(1) y=C, C\neq0

(2) x=C

(1) y=0

Step-by-step explanation:

For the linear equation, the power on the solitary variable must be 1.

When the graph of a function crosses/ touches the x-axis than the equation has solution/solutions otherwise it does not has a solution.

When it touches/cresses the x-axis for infinite times then it will have an infinite number of solutions.

(1) The linear equation y-C=0, where y is a variable and C is a non-zero constant,  C \neq 0, has the graph parallel to the x-axis. It has no solution as the graph will never cross/touch the x-axis.

Algebraically, in linear equation y-C=0, is independent of x, so there is no value of x for the solution to be exist.

(2) The linear equation x-C=0, where x is a variable and C is a constant, has one solution.

The solution for the equation is

x-C=0

\Rightarrow x=C, where C\neq0.

(3) The linear equation y=0, where y is a variable, has the graph coinciding with the x-axis. So, it has infinitely many solutions.

Algebraically, in linear equation y=0, is independent of x, so for all value of x, the given equation is zero. Hence, there are infinitely many solutions.

3 0
4 years ago
Can someone find the surface area please
lozanna [386]
To find the surface area of any object, the first step that you must do is find all shapes that are present in the object.

Here we have 2 triangles and 3 rectangles.

Knowing this, simply find the area of each shape.

Since the triangles are the same, one is facing up and the other down, they both would be 15.6 cm^2.

The rectangles would be 54 cm^2. as there are 3 ( 6 x 3 cm) ones.

Add the values up to have the surface area.

It’s 85.2 cm^2.
3 0
4 years ago
Read 2 more answers
Help pls 2,4 +0,8=........+1,21=........+1,78=........-5,14=
Mrrafil [7]
Lets write this out:-

2.4 + 0.8 = ________ + 1.21 = ______ + 1.78 = ______ - 5.14 = _____

So to solve d blanks we will do d following:-

2.4 + 0.8 = 3.2

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = ______ + 1.78 = ______ - 5.14 = ____

Now lets solve again:-

3.2 + 1.21 = 4.41 

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = ______ - 5.14 = ____

Now lets solve again:-

4.41 + 1.78 = 6.19

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = ____

Now lets solve again:-

6.19 - 5.14 = 1.05

Now lets write this out AGAIN.

2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = 1.05

So, 2.4 + 0.8 = 3.2 + 1.21 = 4.41 + 1.78 = 6.19 - 5.14 = 1.05

Hope I helped ya!! xD 
7 0
3 years ago
A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along
mina [271]

Answer:

The tip of the man shadow moves at the rate of \frac{20}{3} ft.sec

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

\frac{y - x}{y} = \frac{6}{15}

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = \frac{15x}{9\\} y = \frac{5x}{3}

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt} ----(1)

We are given \frac{dx}{dt} = 4 ft/sec. Plug in the equation (1), we get

\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0
3 years ago
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