Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
the answer is 40%
Step-by-step explanation:
Answer:
11 + 16n
Step-by-step explanation:
Collect the like terms
2 + 9 = 11
10n + 6n = 16n
11 + 16n is the final answer, and cannot be simplified further
Answer:
x = 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
Step-by-step explanation:
<u>Step 1: Define</u>
0.4(12 - 3x) = 0.3(12x - 16)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute: 4.8 - 1.2x = 3.6x - 4.8
- Add 1.2x on both sides: 4.8 = 4.8x - 4.8
- Add 4.8 on both sides: 9.6 = 4.8x
- Divide 4.8 on both sides: 2 = x
- Rewrite: x = 2