The answer to your question is 15.6
Answer:
1a. n=7
2a. p=3
3a. m=48
4a. a=81
5a. a=8
6a. p=14
7a. s=60
8a. r=18
9a. n=65
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1b. a=15
2b. b=5
3b. n=10
4b. d=13
5b. e=120
6b. n=45
7b. x=8
8b. x=56
9b. a=96
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1c. b=36
2c. r=120
3c. s=11
4c. m=112
5c. i=272
6c. b=20
7c. a=42
8c. m=11
9c. p=21
Step-by-step explanation:
1. 2n+2= 16
Subtract 2 from each side
2n=14
Divide each side by 2.
n=7
2a. 11p-5=28
Add 5 to each side
11p=33
Divide each side by 11
p=3
3a. m/16 +7=10
Subtract 7 from each side
m/16 =3
multiply each side by 16
m=48
4a. a/9 -3 =6
Add 3 to each side
a/9=9
Multiply each side by 9
a=81
5a. 9a-11=61
Add 11 to each side
9a=72
Divide each side by 9
a=8
6a. 3p+12=54
Subtract 12 from each side
3p=42
Divide each side by 3
p=14
7a. s/15+1=5
Subtract 1 from each side
s/15=4
Multiply each side by 15
s=60
8a. 3r-11=43
Add 11 to each side
3r=54
Divide each side by 3
r=18
9a. n/5 -5=8
Add 5 to each side
n/5=13
Multiply each side by 5
n=65
1b. a/3-1=4
Add 1
a/3=5
Multiply by 3
a=15
2b. 8b+12=52
Subtract 12
8b=40
Divide by 8
b=5
3b. 6n+4=64
Suntract 4
6n=60
Divide by 6
n=10
4b. 5d+6=71
Subtract 6
5d=65
Divide by 5
d=13
5b. e/12-7=3
Add 7
e/12=10
Multiply by 12
e=120
6b. n/3+12=27
Subtract 12
n/3=15
Multiply by 3
n=45
7b. 6x+25=73
Subtract 25
6x=48
Divide by 6
x=8
8b. x/7+14=22
Subtract 14
x/7= 8
Multiply by 7
x=56
9b. a/6+4=20
Subtract 4
a/6=16
Multiply by 6
a=96
1c. b/4+2=11
Subtract 2
b/4=9
Multiply by 4
b=36
2c. r/20-3=3
Add 3
r/20=6
Multiply by 20
r=120
3c. 4s-5=39
Add 5
4s=44
Divide by 4
s=11
4c. m/8+5=14
Subtract 5
m/8=14
Multiply by 8
m=112
5c. i/4+5=73
Subtract 5
i/4=68
Multiply by 4
i=272
6c. 5b-7=93
Add 7
5b=100
Divide by 5
b=20
7c. a/3-3=11
Add 3
a/3=14
Multiply by 3
a=42
8c. 5m+13=68
Subtract 13
5m=55
Divide by 5
m=11
9c. 3p-15=48
Add 15
3p=63
Divide by 3
p=21
One or two may be wrong but that's because I was trying to do the answers quickly.
Hope this helps! If you have any questions on how I got my answer feel free to ask. Stay safe!
I use it all the time, but as my profession is engineering, mathematics is integral in my everyday life. I usually do it when evaluating for the magnitude of vector force components. Usually in 2D space, so Pythagorean theorem is quite useful.
Answer:
B
Step-by-step explanation:
A function cannot have more than one point on the same x coordinate. So, B is the only option that works.
V1=30km/hr
v2=20km/hr
v=2v1v2/(v1+v2)
=2*30*20/(30+20)
=24km/hr
