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Komok [63]
4 years ago
7

At a high school movie night, the refreshment stand sells popcorn and soft drinks. Of the 100 students who came to the movie, 62

bout popcorn and 47 bought a drink. 38 students bought both popcorn and a drink. What is the probability that a student buys a drink?
Mathematics
2 answers:
Colt1911 [192]4 years ago
7 0

Answer:

The probability that a student buys a drink is 0.47.

Step-by-step explanation:

Given : At a high school movie night, the refreshment stand sells popcorn and soft drinks. Of the 100 students who came to the movie, 62 bout popcorn and 47 bought a drink. 38 students bought both popcorn and a drink.

To find : What is the probability that a student buys a drink?          

Solution :

Total number of students are T=100 who came to the movie.

Student who bought popcorn = 62

Student who bought drink = 47

Students who bought both popcorn and a drink = 38

We have to find the probability that a student buys a drink.

Favorable outcome F=47                      

Probability is P=\frac{F}{T}

P=\frac{47}{100}    

P=0.47    

Therefore, The probability that a student buys a drink is 0.47.

Illusion [34]4 years ago
4 0

The answer is 19/50 or 38%.

Hope this helps!

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Step-by-step explanation:

Given <u>vertices</u> of a rectangle:

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As points A and D share the <u>same x-coordinate</u>, and points B and C share the <u>same x-coordinate</u>, the difference between the different <u>x-coordinates</u> is the length of the rectangle:

\begin{aligned}\implies \textsf{Length} & = x_B-x_A\\& = 2-(-8)\\& = 2+8\\& = 10\; \sf units\end{aligned}

As points A and B share the <u>same y-coordinate</u>, and points C and D share the <u>same y-coordinate</u>, the difference between the different <u>y-coordinates</u> is the width of the rectangle:

\begin{aligned}\implies \textsf{Width} & = y_A-y_D\\& = 5-(-3)\\& = 5+3\\& = 8\; \sf units\end{aligned}

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\begin{aligned}\textsf{Area of a rectangle} & = \sf width \times length\\&=8 \times 10\\&=80 \sf \; units^2\end{aligned}

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