What are the coordinates for D,E and F? How do u know? Triangle Mid segment Theorem

Mathematics

1 answer:

Otrada [13]3 years ago

6 0

Answer:

Hope this helps!!

Step-by-step explanation:

F:(-1,-4)

E:(-2,0)

D:(-2,-5)

The Midsegment Theorem states that the midsegment connecting the midpoints of two sides of a triangle is parallel to the third side of the triangle, and the length of this midsegment is half the length of the third side.

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a = 1
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Simplify into standard form:

$\sf x^2+(1-1(5))x+6-4$

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Use the quadratic formula to solve:

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

For functions in the form of $\sf ax^2+bx+c$ . So in this case:

a = 1
b = -4
c = 2

Plug them in:

$\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}$

Solve for 'x':

$\sf x=\dfrac{4\pm\sqrt{16-8}}{2}$

$\sf x=\dfrac{4\pm\sqrt{8}}{2}$

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