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allsm [11]
3 years ago
13

Please help quick!!

Mathematics
2 answers:
UNO [17]3 years ago
3 0

the last one sorry i thought 5 was negative lol

barxatty [35]3 years ago
3 0

Answer:

5 · 5

Step-by-step explanation:

2 + 2 + 2 + 2 + 2 = 10

5 + 5 = 10

2 · 2 · 2 · 2 · 2 = 32

5 · 5 = 25

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What is the inverse of y=^x3
Rashid [163]

Answer:

Inverse of y=x^3 is f^-1(x) = ∛x

Step-by-step explanation:

We need to find the inverse of y=x^3

Step 1:

Interchange the variables:

x= y^3

Step 2: Now solve to find the value of y

=> y^3 = x

taking cube root on both sides of the equation

∛y^3 = ∛x

y=∛x

Step 3: Replace y with f^-1(x)

f^-1(x) = ∛x

So inverse of y=x^3 is f^-1(x) = ∛x

4 0
3 years ago
Which expression is equivalent to (r^5/4
Mademuasel [1]

<u>Answer:</u>

2

<u>Step-by-step explanation:</u>

• Multiplying two numbers with same bases is the same as adding their powers:

∴ (\frac{4^{\frac{5}{4} } \cdot 4^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

⇒ (\frac{4^{\frac{5}{4} } ^ + ^{\frac{1}{4} }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

⇒ (\frac{4^{\frac{6}{4}  }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

• Dividing two numbers with same bases is the same as subtracting their powers:

∴  (\frac{4^{\frac{6}{4}  }}{4^{\frac{1}{2} }})^{\frac{1}{2} }

⇒ (4^{{\frac{6}{4} - \frac{1}{2} }})^{\frac{1}{2} }

⇒  (4^{1})^{\frac{1}{2} }

⇒  4^{\frac{1}{2}

• Raising anything to the power of  \frac{1}{2} is the same as square-rooting it:

∴  4^{\frac{1}{2}

⇒ \sqrt{4}

⇒ 2

3 0
2 years ago
My brother gave me 2/3rd of 63 Dhs. How much money did he give me? tell fast
Nataly_w [17]

answer:42

Step-by-step explanation: divide 63 by 3 then multiply that by 2

6 0
3 years ago
Solve for x. 4x + 5 + 3x= 19
marusya05 [52]

4x+5+3x=19

or, 7x+5=19

or, 7x=19-5

or, 7x=14

or, x=14/7

therefore, x=2

4 0
4 years ago
Read 2 more answers
Explain why the product of a nonzero rational number and an irrational number is irrational
spayn [35]

Answer:

If you multiply any irrational number by the rational number zero, the result will be zero, which is rational. Any other situation, however, of a rational times an irrational will be irrational.

3 0
3 years ago
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