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Vedmedyk [2.9K]
3 years ago
10

My question is in the picture, pls help

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer: I'm pretty sure its term but i'm sorry if its not.

Step-by-step explanation:

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lesya692 [45]
They are not the same shape or size. hope this helps!
4 0
3 years ago
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The perimeter of a square is 40 inches...Determine the area of the square ... A.) 160 square inches B) 10 square *inches C) 100
marysya [2.9K]
P=4s

s=p/4

a=s^2, using s found above

a=p^2/16, we were told that p=40 so

a=40^2/16

a=100 in^2
4 0
3 years ago
What is the equation of the line in point-slope form that has a slope of -3 and passes through the point (5, 9)?
krek1111 [17]

Answer:

y-9=-3(x-5)

Step-by-step explanation:

The equation of the line in point-slope form is given as

y-y_1=m(x-x_1)

Here m=-3 and (x1, y1)=(5, 9)

Therefore,

y-9=-3(x-5)

8 0
3 years ago
Consider the following function. f(x) = 7x + 1 x (a) Find the critical numbers of f. (Enter your answers as a comma-separated li
sukhopar [10]

Answer:

a) DNE

b) The function increases for every real value of x.

c) DNE

Step-by-step explanation:

Given a function f(x), the critical points are those in which f^{\prime}(x) = 0, that is, the roots of the first derivative of f(x).

Those critical points let us find the intervals in which the function increases or decreases. If the first derivative in the interval is positive, the function increases in the interval. If it is negative, the function decreases.

If the function increases before a critical point and then, as it passes the critical point, it starts to decrease, we have that the critical point (x_{c}, f(x_{c}) is a relative maximum.If the function decreases before a critical point and then, as it passes the critical point, it starts to increase, we have that the critical point [tex](x_{c}, f(x_{c}) is a relative minimum.If the function has no critical points, it either always increases or always decreases.In this exercise, we have that:[tex]f(x) = 7x + 1

(a) Find the critical numbers of f.

f^{\prime}(x) = 0

f^{/prime}(x) = 7

7 = 0 is false. This means that f has no critical points.

(b) Find the open intervals on which the function is increasing or decreasing.

Since there are no critical points, we know that either the function increases or decreases in the entire real interval.

We have a first order function in the following format:

f(x) = ax + b

In which a > 0.

So the function increases for every real value of x.

(c) Apply the First Derivative Test to identify the relative extremum.

From a), we find that there are no critical numbers. So DNE

7 0
3 years ago
BRAINIEST, THANKS, AND 5 STAR RATING what is the equation of the line in slope intercept form?
uranmaximum [27]

Answer:

y = -300x

Step-by-step explanation:

The y-intercept passes through 0, in this case, we don't have to include the y intercept to the equation. The slope is -300, or vertical/horizontal (rise/run, the formula for finding slope <<) We just include the slope if there is no y intercept. So, y = -300x is the equation!

8 0
3 years ago
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