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2 years ago

Find the surface area of a square pyramid with side length 4 yd and slant height 6 yd.

Mathematics

1 answer:

elena-s [515]2 years ago

4 0

Answer:

112 yd²

Step-by-step explanation:

Surface area of the square pyramid = area of base + perimeter of base × slant height

Area of base = s²

s = 4 yd

Area = 4² = 16 yd²

Perimeter = 4(s)

Perimeter = 4(4) = 16 yd

Slant height = 6 yd

Surface area of the square pyramid = 16 + 16 × 6

= 16 + 96

= 112 yd²

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Complete the statements about the series

AleksAgata [21]

Answer:

Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.

This means that the value of k will go from 0 to 4, then all the numbers in the sum are:

(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4

So we have 5 terms in our series.

b) to see the sign in each term, we must solve the powers, remember that:

(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:

(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4

= 1 -1/2 + 1/4 - 1/8 + 1/16.

So the sign in each term of the series alternates.

4 0

3 years ago

Guys, Can you please help me with these questions

MakcuM [25]

Answer:

a) $w^{13} x^{5} y^{6}$

b) $\frac{x}{3y^{6} }$

Step-by-step explanation:

a) $(w^{2} xy^{3} )^{2}(w^{3}x )^{3}$

1. Distribute the second power (2) outside the first pair of parenthesis:

$(w^{2(2)} x^{2} y^{3(2)} )$

= $w^{4} x^{2} y^{6} (w^{3}x )^{3}$

2. Distribute the third power (3) outside the second pair of parenthesis:

$(w^{3(3)} x^{3} )$

= $w^{4} x^{2} y^{6} w^{9} x^{3}$

3. Combine like terms:

$w^{13} x^{5} y^{6}$

--------------------------------------------

b) $\frac{2x^{2} y^{5} }{6xy^{11} }$

1. Factor the number 6 (= 2 · 3):

$\frac{2x^{2} y^{5} }{2(3)xy^{11} }$

2. Cancel the common factor (2):

$\frac{x^{2} y^{5} }{3xy^{11} }$

3. Cancel out $xy^{5}$ in the numerator an denominator:

$\frac{x}{3y^{6} }$

hope this helps!

4 0

2 years ago

What is the product?

hammer [34]

Answer:

3/88 is your answer

Step-by-step explanation:

4 0

2 years ago

The location of point V is (-3,3). The location of point X is (9,13). Determine the location of point W which is 3/4 of the way

Inga [223]

ANSWER

$W(\frac{9}{7},\frac{51}{7} )$

EXPLANATION

We want to find the coordinates of the point W(x,y) which divides V(-3,3) and X(9,13) in the ratio m:n=3:4.

The x-coordinate of this point is given by:

$x= \frac{mx_2+nx_1}{m + n}$

$x= \frac{3(9)+4( - 3)}{4 + 3}$

$x= \frac{21 - 12}{4 + 3}$

$x= \frac{9}{7}$

The y-coordinates is given by;

$y= \frac{my_2+ny_1}{m + n}$

$y= \frac{3(13)+4( 3)}{4 + 3}$

$y= \frac{39+12}{4 + 3}$

$y= \frac{51}{7}$

Hence

$W(\frac{9}{7},\frac{51}{7} )$

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3 years ago

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nadya68 [22]

Answer:

Step-by-step explanation:

8 0

2 years ago

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