Answer:
56
Step-by-step explanation:
(-2)(-4)(-1)(-7)(1) =
(8)(-1)(-7)(1) =
(-8)(-7)(1) =
(56)(1) = 56
hope this helps
have a good day
You are correct about the y-intercept. In case you are unsure about the slope, you can check using y1 - y2 / x1 - x2:
(0, -1) and (1, 2)
-1 - 2 / 0 - 1
-3 / -1
3
The slope is 3; you chose the correct answer, great job.
Steps:
(x-2)=4x
Pretend that there is a one in front of x-2
1(x-2)=4x
Multiply the bracket by 1
x-2=4x
Move x to the other side .Whenever you move a number or letter the sign changes.
x-x-2=4x-x
-2=3x
Divide by 3 for -2 and 3
-2/3=3/3 x
x=-2/3
Check answer by using substitution method
(-2/3-2)=4(-2/3)
(-2/3-6/3)=-8/3
-8/3=-8/3
Answer is -2/3
Answer:
(a) Probability that a triplet is decoded incorrectly by the receiving computer. = 0.010
(b)
(1 – p) = 0.010
(c)
E(x) = 25000 x 0.010
= 259.2
Explanation has given below.
Step-by-step explanation:
Solution:
(a) Probability that a triplet is decoded.
2 out of three
P = 0.94, n = 3
m= no of correct bits
m bit (3, 0.94)
At p(m≤1) = B (1; 3, 0.94)
= 0.010
(b) Using your answer to part (a),
(1 – p) = 0.010
Error for 1 bit transmission error.
(c) How does your answer to part (a) change if each bit is repeated five times (instead of three?
P( m ≤ 2 )
L = Bit (5, 0.94)
= B (2; 5, 0.94)
= 0.002
(d) Imagine a 25 kilobit message (i.e., one requiring 25,000 bits to send). What is the expected number of errors if there is no bit repetition implemented? If each bit is repeated three times?
Given:
h = 25000
Bits are switched during transmission between two computers = 6% = 0.06
m = Bit (25000, 0.06)
E(m) = np
= 25000 x 0.06
= 1500
m = Bit (25000, 0.01)
E(m) = 25000 x 0.010
= 259.2
