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lisov135 [29]
3 years ago
6

Answer in factored form 13+14m+m^2

Mathematics
2 answers:
eduard3 years ago
6 0
What 2 numbers multiply to 13 and add to 14?
13 and 1
(1+m)(13+m)
natta225 [31]3 years ago
5 0
<span>Solution


m = {-13, -1}</span>
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A rectangle with a length of L and a width of W has a diagonal of 10 inches. Express the perimeter P of the rectangle as a funct
KatRina [158]
<h2>Answer:</h2>

The expression which represents the perimeter P of the rectangle as a function of L is:

          Perimeter=2(L+\sqrt{100-L^2})

<h2>Step-by-step explanation:</h2>

The length and width of a rectangle are denoted by L and W respectively.

Also the diagonal of a rectangle is: 10 inches.

We know that the diagonal of a rectangle in terms of L and W are given by:

10=\sqrt{L^2+W^2}

( Since, the diagonal of a rectangle act as a hypotenuse of the right angled triangle and we use the Pythagorean Theorem )

Hence, we have:

10^2=L^2+W^2\\\\i.e.\\\\W^2=100-L^2\\\\W=\pm \sqrt{100-L^2}

But we know that width can't be negative. It has to be greater than 0.

Hence, we have:

W=\sqrt{100-L^2}

Now, we know that the Perimeter of a rectangle is given by:

Perimeter=2(L+W)

Here we have:

Perimeter=2(L+\sqrt{100-L^2})

7 0
3 years ago
What is the approximate volume of the cone?
Vlad [161]
Volume=1/3π<span>×</span>r²×h^(Applies for any "right cone")^
Therefore your answer would be 
A.1206 cm³

8 0
3 years ago
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Phoebe took a survey of her classmates' favorite sport. The results are in the table below:
olga55 [171]

Answer:

.14

Step-by-step explanation:

7 0
3 years ago
Explain why 1/2 of 2 equals one whole
Darya [45]
1/2 of 2 means you're taking a half of 2. Which 1.
8 0
3 years ago
find the value of x of given figure and solve this question step by step plzz help question number D​​
Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm

Applying Pythagoras theorem:

(Hypotenuse)^2  = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm

Solving for triangle ABC

Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\

Applying Pythagoras theorem

AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm

Hence,

x=15 cm

8 0
2 years ago
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