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2 years ago

Solve for x, and JUSTIFY your answer

Mathematics

1 answer:

Rashid [163]2 years ago

7 0

Answer:

Step-by-step explanation:

every angle is the same and 1/3 of 180 is 60

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*7.NS.1: Apply and extend previous understandings of addition and subtraction to add and subtract rational numbers;

aleksandrvk [35]

Answer:

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Step-by-step explanation:

5 0

2 years ago

Tonla is saving $15.00 each week to buy a bicycle. The bicycle costs $129.99. Which inequality can be used to determine the numb

Alex

Answer:

15.00w < 129.99

hope it helps

6 0

2 years ago

Chuck chooses an investment plan that requires him to make a one-time investment of $10,000, and then equal monthly investments

Pepsi [2]

As the function is

y = 10,000 + 350x , Here x is the number of months elapsed and y is the amount after x number of months.

This function is for the form

y = mx +b or y = b +mx

which is the form of a linear equation

So the given function is a linear function.

So a is true

a)The function is a linear function.

Also The function is increasing at a constant rate , So options C and E are also correct

A, C and E

8 0

3 years ago

Read 2 more answers

Find the area of a parallelogram with base b and height h. b = 87 cm h = 18.6 cm A.105.6 cm2 B.2 211.2 cm2 C809.1 cm2 D1,618.2 c

Bingel [31]

I hope this helps you

Area of parallelogram =base×height

Area =87×18,6

Area =1618,2

5 0

3 years ago

find the zeros of following quadratic polynomial and verify the relationship between the zeros and the coefficient of the polyno

Cloud [144]

Answer:

$\textsf{Zeros}: \quad x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}$

Step-by-step explanation:

Rewrite the given polynomial in the form ax² + bx + c:

$f(x)=2 \sqrt{3}x^2+5x-4 \sqrt{3}$

To find the zeros, set the function to zero and solve for x using the quadratic formula.

$\implies 2 \sqrt{3}x^2+5x-4 \sqrt{3}=0$

<u>Quadratic formula</u>:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore,

a = 2√3
b = 5
c = - 4√3

Substituting the values into the quadratic formula:

$\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2\sqrt{3})(-4\sqrt{3})} }{2(2\sqrt{3})}$

$\implies x=\dfrac {-5 \pm \sqrt {121}}{4\sqrt{3}}$

$\implies x=\dfrac {-5 \pm 11}{4\sqrt{3}}$

$\implies x=\dfrac {6}{4\sqrt{3}}, \:\:x=\dfrac {-16}{4\sqrt{3}}$

$\implies x=\dfrac {3}{2\sqrt{3}}, \:\:x=-\dfrac {4}{\sqrt{3}}$

$\implies x=\dfrac {\sqrt{3}}{2}, \:\:x=-\dfrac {4\sqrt{3}}{3}$

The sum of the roots of a polynomial is -b/a:

$\implies -\dfrac{b}{a}=-\dfrac{5}{2 \sqrt{3}}=-\dfrac{5\sqrt{3}}{6}$

The sum of the found roots is:

$\implies \left(\dfrac {\sqrt{3}}{2}\right)+\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{5\sqrt{3}}{6}$

Hence proving the sum of the roots is -b/a

The product of the roots of a polynomial is: c/a

$\implies \dfrac{c}{a}=\dfrac{-4\sqrt{3}}{2\sqrt{3}}=-2$

The product of the found roots is:

$\implies \left(\dfrac {\sqrt{3}}{2}\right)\left(-\dfrac {4\sqrt{3}}{3}\right)=-\dfrac{12}{6}=-2$

Hence proving the product of the roots is c/a

Therefore, the relationship between the roots and the coefficients is verified.

8 0

1 year ago