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3 years ago

8

2 triangles are shown. The first triangle has side lengths 15, 15, and 21. The second triangle has side lengths 20, 20, x. What

value of x will make the triangles similar by the SSS similarity theorem? x =

2 answers:

BlackZzzverrR [31]3 years ago

7 0

Answer:

28

Step-by-step explanation:

got it right one edge.

olga55 [171]3 years ago

3 0

Answer:

28

Step-by-step explanation:

Just answered it

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Phoenix [80]

By applying <em>radical</em>, <em>power</em> and <em>rational</em> properties we have the following results after simplifying expressions:

$x^{\frac{3}{4} }$
x
$x^{\frac{11}{10} }$
x

<h3>How to reduce radical and rational expressions into a single power expression with rational exponent</h3>

In this question we need to simplify four given expressions by using the following <em>radical</em> and <em>power</em> properties:

$\sqrt[n]{x} = x^{\frac{1}{n} }$ (1)
$x^{m+n} = x^{m}\cdot x^{n}$ (2)
$x^{m-n} = \frac{x^{m}}{x^{n}}$ (3)
$(x^{m})^{n} = x^{m\cdot n}$ (4)

Now we proceed to simplify each of the four expressions:

$\sqrt[4]{x^{3}} = x^{3/4}$
$\frac{1}{x^{-1}} = (x^{-1})^{-1} = x$
$\sqrt[10]{x^{5}\cdot x^{4}\cdot x^{2}} = \sqrt[10]{x^{11}} = x^{\frac{11}{10} }$
$x^{\frac{1}{3} }\cdot x^{\frac{1}{3} }\cdot x^{\frac{1}{3} } = x$

To learn more on power functions: brainly.com/question/18719083

#SPJ1

3 0

3 years ago

The volume of a cylinder is 30 pie cubic units. A cone shares the same base. The height of the cone is twice the height of the c

bija089 [108]

<u>Given</u>:

The volume of a cylinder is $30 \pi$ cubic units.

A cone shares the same base.

The height of the cone is twice the height of the cylinder.

We need to determine the volume of the cone.

<u>Height of the Cone:</u>

Let h denote the height of the cylinder.

Let H denote the height of the cone.

Since, it is given that, the height of the cone is twice the height of the cylinder, we have;

$H=2h$

<u>Volume of the cylinder:</u>

The formula to determine the volume of the cylinder is

$V=\pi r^2 h$

Since, volume of the cylinder is $30 \pi$ , we get;

$30 \pi = \pi r^2 h$ -------(1)

<u>Volume of the cone:</u>

The formula to determine the volume of the cone is

$V=\frac{1}{3} \pi r^2 H$

Substituting $H=2h$ , we get;

$V=\frac{1}{3} \pi r^2 (2h)$

$V=\frac{2}{3} \pi r^2 h$

Substituting equation (1), we get;

$V=\frac{2}{3} (30 \pi)$

$V=20 \pi$

Thus, the volume of the cone is 20π

Hence, Option C is the correct answer.

4 0

4 years ago

Find the zeros of f(x)=x^2+2x-8

NeTakaya

Answer:

(x - 2) (x +4)

Step-by-step explanation:

Find what two numbers multiplied make -8 and those same numbers will equal 2 when they are subtracted. So...

4 x -2 = 8

4 - 2 = 2

So, (x - 2) (x + 4)

7 0

3 years ago

Read 2 more answers

4x+y=15 <br> 3x+5y=41<br> help please!

NemiM [27]

Step-by-step explanation:

x=2. y=7

4(2) + (7) =15

3(2) + 5(7) = 41

3 0

3 years ago

Read 2 more answers

Assume that in October of a particular year about 215 billion text messages were sent or received in the US, and the prediction

Julli [10]

Answer:

There will be $243$ billion messages sent or received in November.

Step-by-step explanation:

Given.

Number of text messages sent or received $=215$ billion.

Increment on the very next month $=13\%=\frac{13}{100}=0.13$

Lets find what is $13\%\ of\ 215$

⇒ $13\%\ of\ 215$

⇒ $0.13\times 215=27.95$

So we will add this value to our previous months data.

Now

Number of text messages sent in the month of November $=(27.5+215)=242.95$ billion.

Rounding to the nearest tenth the answer will be $243$ billion.

So $243$ billion text messages were sent or received in November.

5 0

3 years ago