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2 years ago

What is the value of s ?

Mathematics

2 answers:

Rom4ik [11]2 years ago

6 0

36.7 degrees Hope it helps

Leto [7]2 years ago

5 0

Answer:

36.7 degrees. A straight line is 180 degrees.

Step-by-step explanation:

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Suppose a1={1,{2}}a1={1,{2}} and a2={∅,{1,2}}a2={∅,{1,2}} and a3={∅,{1},2}a3={∅,{1},2}. enter "t" for each true, and "f" for eac

lbvjy [14]

P=a=b=p4/6 hope this helps :)))))

6 0

3 years ago

60 is 150% of which number?

sweet [91]

Answer:

Step-by-step explanation:

5 0

2 years ago

Autum school holding a voleturing challeng. Students are encouraged to volunteer for at least 1 1/2 hours per week. Volenteers a

Pani-rosa [81]

Given :

Challenge given is to volunteer for about 1 1/2 hours per week .

Autum did at a rate of 6 3/4 hours per week .

To Find :

The comparison ( ratio ) her volunteers rate with the challenge rate .

Solution :

Simplifying challenge rate in in normal fraction , $1\dfrac{1}{2}=\dfrac{2+1}{2}=\dfrac{3}{2}$ .

Also , simplifying her rate , $6\dfrac{3}{4}=\dfrac{(6\times 4)+3}{4}=\dfrac{27}{4}$ .

Now , ratio of his work by challenge is :

$R=\dfrac{\dfrac{27}{4}}{\dfrac{3}{2}}\\\\\\R=\dfrac{27\times 2}{4\times 3}\\\\R=\dfrac{9}{2}$

Therefore , the ratio is 9/2 or 4 1/2 .

Hence , this is the required solution .

8 0

3 years ago

Read 2 more answers

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

3 0

2 years ago

Find the product. (10^2)^3 <br> 1,000 <br> 10,000 <br> 100,000 <br> 1,000,000

dangina [55]

The answer is 1000000
10^2=100
100^3=1000000

3 0

2 years ago