Which set of statements explains how to plot a point at the location (Negative 3 and one-half, negative 2)?

Mathematics

2 answers:

Nimfa-mama [501]2 years ago

6 0

Answer:

d is the answer

Step-by-step explanation:

just read the statements properly

podryga [215]2 years ago

5 0

Answer: Move 3 and one-half units right because the x-coordinate is Negative 3 and one-half. Negative 3 and one-half is between 3 and 4.

IT'S A

You might be interested in

Darin can purchase tile at a store for 0.79 per tile and rent a tile saw for $24. At another store, he can borrow the tile saw f

ankoles [38]

Let us denote the number of tiles by $T$ .

In the first store, if Darin bought $T$ tiles, he would need to spend:
                        $0.79\times T+24$ (measured in $)

In the second store, if Darin bought $T$ tiles, he would need to spend:
                        $1.19\times T$ (measured in $)

For the cost to be the same at both stores, it means (measured in $)
                                           $1.19T=0.79T+24$

Moving $0.79T$ over to the left hand side and changing signs:
                                            $1.19T-0.79T=24$
                                            $0.4T=24$
                                            $T= \frac{24}{0.4}$
                                            $T=60$ tiles

Let's check. If he buys 60 tiles in the first store, he spends:
      $0.79×60 + $24 = $47.40 + $24 = $71.40

If he buys 60 tiles in the second store, he spends:
                               $1.19×60 = $71.40

∴ Darin needs to buy 60 tiles for the cost to be the same at both stores.

7 0

3 years ago

Make B the subject of the relation : 1/a is equal to 1/b + c

stealth61 [152]

Answer:

By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

1/a - 1/b = 1/c : add 1/b to both sides

1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]