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jeka94
2 years ago
5

WHOEVER HELPS AND GETS IT RIGHT I WILL GIVE BRAINLY!!!!!

Mathematics
2 answers:
SOVA2 [1]2 years ago
5 0
Option 3 I believe is correct
vodomira [7]2 years ago
4 0

Answer:

3

Step-by-step explanation:

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At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the
Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8

The range of possible values of w is  w meters (of course w has to be greater than 0)

5 0
3 years ago
#54 Simplify and write the answers using positive exponents only.
kramer
Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}=
( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}=
(2^{-3})((m^2)^{-3})((n^{-4})^{-3})=
( \frac{1}{2^3})(m^{-6})(n^{12})=
( \frac{1}{8} )( \frac{1}{m^6})(n^{12})=
\frac{n^{12}}{8m^6}

8 0
3 years ago
If 8 out of 40 students picked pizza for lunch today what percentage pick Pizza
artcher [175]
20% because 10% of 40 is 4 so 4+4=8 then that is 10%+10% so 20% will be your answer. :)
5 0
3 years ago
Read 2 more answers
Can the vertex also be a solution of a graphed parabola?
stiv31 [10]
One important feature of the parabola is that it has an extreme point, called the vertex. If the parabola opens up, the vertex represents the lowest point on the graph, or the minimum value of the quadratic function.
4 0
3 years ago
If y is a differentiable function of x, then the slope of the tangent to the curve xy-2y 4y^2=6 at the point where y=1 is
Molodets [167]
<span>x(1^2)-2(1)+4(1^3)=6
x - 2 + 4 = 6
x + 2 = 6
x = 4 </span>
7 0
3 years ago
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