All categories

3 years ago

- Calculate the median and range

Mathematics

1 answer:

Igoryamba3 years ago

3 0

I’m not sure but here’s a method that might help: write out the numbers least to greatest, the dots each represent one number, then remember that you add and divide for the mean( add up all the numbers then divide them by how many dots there are) and for median it’s the middle number, if there’s two in the middle add them and divide it by 2

You might be interested in

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

Mandarinka [93]

Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

$a_n = a_m + (n-m)d$

a3 = -12 and a8 = -37

First we find the common difference. So

$a_n = a_m + (n-m)d$

$a_8 = a_3 + (8-3)d$

$-37 = -12 + 5d$

$5d = -25$

$d = -\frac{25}{5}$

$d = -5$

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

6 0

3 years ago

WILL GIVE BRANLIEST!!! Pls help! Determine the coordinates of the point on the straight line y=3x+1 that is equidistant from the

iren [92.7K]

Let , coordinate of points are P( h,k ).

Also , k = 3h + 1

Distance of P from origin :

$d=\sqrt{h^2+k^2}$

Distance of P from ( -3, 4 ) :

$d=\sqrt{(h+3)^2+(k-4)^2}$

Now , these distance are equal :

$h^2+(3h+1)^2=(h+3)^2+(3h+1-4)^2\\\\h^2+(3h+1)^2=(h+3)^2+(3h-3)^2$

Solving above equation , we get :

$P=(\dfrac{16}{21},\dfrac{23}{7})$

Hence , this is the required solution.

6 0

3 years ago

Evaluate C(n, n). A. 0 B. 1 C. n

horrorfan [7]

$C(n,n)=\dfrac{n!}{n!(n-n)!}=\dfrac1{0!}=\dfrac11=1$

In other words, how many ways are there to choose $n$ objects from a total of $n$ objects? Just one; take all of them at the same time.

4 0

3 years ago

Find the value of 5! A. 25 B. 20 C. 120 D. 15

zvonat [6]

Answer:

C 120

Step-by-step explanation:

7 0

2 years ago

-3m+10=25 need this fast please!

Ymorist [56]

Answer:

m=-5

Step-by-step explanation:

7 0

3 years ago