Let V = the launch velocity
Let θ = the launch angle
Let d = the horizontal distance traveled
Ignore air resistance.
The horizontal component of velocity is
u = V cos θ
The time of flight is
t = d/(V cosθ) = (d/V) secθ
Create a table of θ versus t as shown below.
θ t/(d/V)
---- ----------
45 1.4142
40 1.3054
35 1.2208
30 1.1547
The graph shows that as the launch angle decreases below 45°, the time of flight decreases.
Therefore arrow b (θ < 45°) arrives first.
Answer: Arrow b arrives first.
Answer:
A
Step-by-step explanation:
2 ¾= 11/4 Fraction. greater than 1 is 5/4.So, two 5/4 fits in 11/4. So, answer is 2.
Use the break even formula below. You should be able to figure it out.
Break Even = (fixed cost)/(price - variable costs)
