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3 years ago

Help please, :(((((((((((((((((((

Mathematics

2 answers:

pentagon [3]3 years ago

7 0

Around 41.3 times more

ASHA 777 [7]3 years ago

6 0

It’s about 41.3 times more! hope this helped:)

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The midfield highschool soccer team 24 matches last season and won less than 3/4 of them. what is the most number of matches the

scoundrel [369]

Answer:

x < 18

Step-by-step explanation:

3/4 of 24 is 18

So, they had to win less than 3/4 of them, so if x is matches won, it has to be:

x < 18.

5 0

3 years ago

Answer set notation Please answer fast

Ira Lisetskai [31]

Answer:

The set notation for the diagram is P-Q

5 0

2 years ago

The patient recovery time from a particular surgical procedure is normally distributed with a mean of 4 days and a standard devi

Gelneren [198K]

Answer:

a) N(4, 1.6)

b) 4 days

c) $Z = 0.69$

d) There is a 30.85% probability of spending more than 4.8 days in recovery.

e) There is a 11.62% probability of spending between 3.2 and 3.7 days in recovery.

f) The 90th percentile for recovery times is 6.05 days.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Mean of 4 days and a standard deviation of 1.6 days. So $\mu = 4, \sigma = 1.6$ .

a. What is the distribution of X?

This is normal with mean 4 and standard deviation 1.6. So N(4, 1.6).

b. What is the median recovery time?

For the normal distribution, the median is the same as the mean. So the median recovery time is 4 days.

c. What is the Z-score for a patient that took 5.1 days to recover?

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.1 - 4}{1.6}$

$Z = 0.69$

d. What is the probability of spending more than 4.8 days in recovery?

This probability is 1 subtracted by the pvalue of Z when $X = 4.8$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8 - 4}{1.6}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915.

This means that there is a 1-0.6915 = 0.3085 = 30.85% probability of spending more than 4.8 days in recovery.

e. What is the probability of spending between 3.2 and 3.7 days in recovery?

This probability is the pvalue of Z when X = 3.7 subtracted by the pvalue of Z when X = 3.2. So:

X = 3.7

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.7 - 4}{1.6}$

$Z = -0.19$

$Z = -0.19$ has a pvalue of 0.4247

X = 3.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.2 - 4}{1.6}$

$Z = -0.5$

$Z = -0.5$ has a pvalue of 0.3085

This means that there is a 0.4247 - 0.3085 = 0.1162 = 11.62% probability of spending between 3.2 and 3.7 days in recovery.

f. The 90th percentile for recovery times is

This probability is the value of X when Z has a pvalue of 0.90. So it is X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 4}{1.6}$

$X = 4 = 1.28*1.6$

$X = 6.05$

The 90th percentile for recovery times is 6.05 days.

7 0

3 years ago

Eileen drove for 85 minutes. This is 21 more minutes than one third the number of minutes Ethan drove. How do I put this into an

Lapatulllka [165]

So let's start out by labeling Ethan as X

Since 85 is 1/3 of what Ethan drove, that means Ethan drove 3 times of 85.

85= (3x) -21
85 -21 = 3x
60=3x
20 = x

6 0

3 years ago

Read 2 more answers

The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:

Crank

Answer:

Step-by-step explanation:

4 0

3 years ago