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3 years ago

Which statement best describes the product of 4/5 x 10?

Mathematics

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

Step-by-step explanation:

4/5 x 10/1= 40/5

40 divided by 5 equals 8

The answer is 8

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I need help with this so can I get help

Mashcka [7]

Answer:

Step-by-step explanation:

DCB = 180-ACD = 180-58 = 122

ECB = DCB/2 = 122/2 = 61

6 0

3 years ago

Someone please help!

erastova [34]

Answer:

k = 6.26

Step-by-step explanation:

Find the midpoint of each frequency range, multiply that number by the frequency, sum up and divide by the total frequency.

This will give the mean number.

[17*( 3 + 3.5)/2 + 21*(3.5 + k)/2 + 33*(k + 4)/2 + 54*(4 + 4.5)/2 + 15*(4.5 + 6)/2]/140 = 4.09
55.25 + 10.5k + 36.75 + 16.5k + 66 + 229.5 + 78.75 = 140*4.09
17k + 466.25 = 572.6
17k = 572.6 - 466.25
17k = 106.35
k = 106.35/17
k = 6.26

Note, I expected the value of k between 3.5 and 4. This is a bit of illogical outcome.

8 0

3 years ago

Write the equation of the line in slope-intercept form that is perpendicular to Y= 5x +4 and passes through the origin.

tatyana61 [14]

Answer:

y=-1/5x

For the equation of the line in slop intercept form

6 0

3 years ago

What is the solution of the system?

tresset_1 [31]

Answer:

O(4.-1.5) should be the answer

5 0

3 years ago

Find (f • g) (x) Assume x>0

lisabon 2012 [21]

Answer:

$\textsf{B.} \quad (f \cdot g)(x)=10x$

Step-by-step explanation:

Given:

$\begin{cases}f(x)=\sqrt{50x}\\g(x)=\sqrt{2x}\end{cases}$

$\begin{aligned}\textsf{As }(f \cdot g)(x) & = f(x) \cdot g(x)\\\implies (f \cdot g)(x)& = \sqrt{50x} \cdot \sqrt{2x}\end{aligned}$

$\textsf{Apply radical rule} \quad \sqrt{a}\sqrt{b}=\sqrt{ab}:$

$\begin{aligned}\implies (f \cdot g)(x) &= \sqrt{50x2x}\\& = \sqrt{100x^2}\end{aligned}$

Rewrite 100 as 10²:

$\implies (f \cdot g)(x)=\sqrt{10^2x^2}$

$\textsf{Apply exponent rule} \quad a^bc^b=(ac)^b:$

$\implies (f \cdot g)(x)= \sqrt{(10x)^2}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies (f \cdot g)(x)=10x$

6 0

2 years ago