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Nezavi [6.7K]
3 years ago
12

ASAP PLEASE ANSWER THIS WILL GIVE BRAINLIEST

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

Therefore,

The Dimensions are,

Length = 34\ cm\\\\Width = 9\ cm

Step-by-step explanation:

Given:

Perimeter of a rectangle,

Perimeter = 86 cm

let "x" be the width of rectangle,

Width = x

then according to the given condition,

length will be given as,

Length = 3x+7

To Find:

Length =?

Width =?

Solution:

Perimeter of rectangle is given by,

\textrm{Perimeter of Rectangle}=2(Length+Width)

Substituting the values we get

86=2(3x+7+x)\\\\86=2(4x+7).........Equation\\\\86=8x+14\\\\8x=86-14=72\\\\x=\dfrac{72}{8}=9\ cm

Substituting "x" in Length we get

Length = 3\times 9 +7=34

Also Area Of Rectangle is given by

\textrm{Areaof Rectangle}=(Length\times Width)=34\times 9=306\ cm^{2}

Therefore,

The Dimensions are,

Length = 34\ cm\\\\Width = 9\ cm

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frutty [35]

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Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
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∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

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