A farm had 480 acres more wheat than corn. Let use "W" to represent the Wheat and let use "C" to represent the corn. Hence, we have below:
W=C+480
The farmers collected 80% of the wheat and 25% of the corn and the area of the wheat is 300 acres less than the area of the corn:
W-0.8W=C-0.25C+300
0.2W=0.75C+300
We have two equations, two unknowns:
0.2(C+480)=0.75C+300
0.2C+96=0.75C+300
0.55C=294
C=534.55
Answer:
C because its the only one that fits the question its asking. 12-6 8-4 4-2
Step-by-step explanation:
Answer:
Option E) 61.6
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100 bushels per acre
Standard Deviation, σ = 30 bushels per acre
We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.
Formula:

P(X>x) = 0.90
We have to find the value of x such that the probability is 0.90
P(X > x)
Calculation the value from standard normal table, we have,

Hence, the yield of 61.6 bushels per acre or more would save the seed.
It would be Answer A) x>6
Answer:
x>7
Step-by-step explanation:
We do 2 steps
2x > x + 7
that means
2x - x > x - x + 7
then
x > 7
That is the answer. Hope it useful for you!