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3 years ago

14

What is this? Please answer if you know what u are doing

1 answer:

timofeeve [1]3 years ago

6 0

Answer:

$m = 6$

Step-by-step explanation:

$\frac{15}{10} = \frac{m}{4}$

$15 \times 4 = 10m$

$60 = 10m$

$\frac{60}{10} = \frac{10m}{10}$

$6 = m$

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There are 6 boys and 9 girls in the church's youth group. What type of ratio is boys to girls

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3 years ago

Definition: The probability of an occurrence of a single event is called ___ probability.

Sonja [21]

Answer:

1/6

Step-by-step explanation:

A six sided die has 6 options, you can roll a 1,2,3,4,5,6. You cannot "remove" numbers and with a single die, you can't roll anymore than one number at a time. 2 is one option out of 6, therefore your answer is 1/6.

8 0

3 years ago

Read 2 more answers

Khalid carried water bottles to the field to share with his team at halftime. The water bottles weighed

jeka57 [31]

Answer:

<u>Answer</u><u>:</u><u> </u><u>D</u>

${50x}^{2} + 30x + 10$

• first factorise out 10:

$= 10(5 {x}^{2} + 3x + 1)$

• then find factors of the quadratic equation in the bracket:

4 0

3 years ago

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago