i think the answer is 0.001853
Answer:

Step-by-step explanation:
The 90th percentile of a normally distributed curve occurs at 1.282 standard deviations. Similarly, the 10th percentile of a normally distributed curve occurs at -1.282 standard deviations.
To find the
percentile for the television weights, use the formula:
, where
is the average of the set,
is some constant relevant to the percentile you're finding, and
is one standard deviation.
As I mentioned previously, 90th percentile occurs at 1.282 standard deviations. The average of the set and one standard deviation is already given. Substitute
,
, and
:

Therefore, the 90th percentile weight is 5.1282 pounds.
Repeat the process for calculating the 10th percentile weight:

The difference between these two weights is
.
Answer:
Step-by-step explanation:
1) Given figure is a parallelogram
Area = 144 cm²
base * altitude = 144
16 * x = 144
x =144/16
x = 9 cm
2)2) Trapezium
Area =
; {a and b are parallel sides of trapezium}
( 37 +27 /2) * x = 480 cm²
64/2 * h = 480
32 * h = 480
h = 480/32
h = 15 cm
Answer:
you have to use graph to make it bro
Step-by-step explanation:
hope it will help you