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dangina [55]
3 years ago
6

I don’t know the answer and I’m doing a text I need help!

Mathematics
1 answer:
swat323 years ago
8 0

Answer:

your answer will be A

Step-by-step explanation:

^_^

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Where you take a word problem and turn it into an equation
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Find the arc length of the semicircle. Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a d
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

The formula for the length of an arc is s = rФ.

Thus, the arc length of a semicircle is S = rФ/2.

Here the radius is 5 (half the diameter), and so in this case the arc length is

S = (5 units)π/2, or S = (5/2)(3.14) units, or approximately S = 7.85 units

6 0
3 years ago
What is the area of a trapezoid if the base is 5, 17, 5 and height is 4
Snowcat [4.5K]

Answer:

Step-by-step explanation:

Trapezoid

Solve for area

A=44

a Base  

5

b Base  

17

h Height  

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7 0
3 years ago
-30 < x/-4 must be simplified​
Norma-Jean [14]

Answer:

120 > x

Step-by-step explanation:

multiply -4 on both sides, -30 * -4 = 120

since you multiplied by a negative you change the sign

<3

7 0
3 years ago
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D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
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