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3 years ago

Consider the infinite geometric series 2(p-5) + 2(p-5)² + 2(p-5)³

Mathematics

1 answer:

nasty-shy [4]3 years ago

7 0

10(p+3)-4(p+10)-6(p+15)

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-59_________-60 < > =

OLga [1]

Answer:

Step-by-step explanation:

-59 is bigger than -60. If you think about it on a number line, it is bigger.

By the way, can you follow me on Brainly?

Thanks!

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3 years ago

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Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is

kodGreya [7K]

We're looking for a scalar function $f(x,y)$ such that $\nabla f(x,y)=\vec F(x,y)$ . That is,

$\dfrac{\partial f}{\partial x}=2x-6y$

$\dfrac{\partial f}{\partial y}=-6x+6y-7$

Integrate the first equation with respect to $x$ :

$f(x,y)=x^2-6xy+g(y)$

Differentiate with respect to $y$ :

$-6x+6y-7=-6x+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=6y-7$

Integrate with respect to $y$ :

$g(y)=3y^2-7y+C$

So $\vec F$ is indeed conservative with the scalar potential function

$f(x,y)=x^2-6xy+3y^2-7y+C$

where $C$ is an arbitrary constant.

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3 years ago

2.(03.01 LC)

ale4655 [162]

592,722 is the correct answer

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3 years ago

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Find the sum of the first 25 multiples of 10.

poizon [28]

Answer:

Step-by-step explanation: So the first 25 multiples of 10 are ,

10,10,10,10 ect, to 25 the sum of all of the numbers is 250 i hope this helped!!!

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3 years ago

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What is the leading coefficient of the polynomial when written in standard form? 872 +9+ 5x

lianna [129]

Answer:

Step-by-step explanation:

The coefficient is known as "the number in front of the letter,' so since 5 is in front of the x, 5 would be the leading coefficient, especially since the outcome would be 5x+881.

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3 years ago

Consider the infinite geometric series 2(p-5) + 2(p-5)² + 2(p-5)³​

Consider the infinite geometric series 2(p-5) + 2(p-5)² + 2(p-5)³