<span>5.42465753425
</span>79.2÷14.6
X is equal to 11/30 because, using basic moves, you subtract the 2 4/5 from either side to get x by itself. So 3 1/6 - 2 4/5 = 11/30. Then you are left with x = 11/30.
The slope-intercept form:
y = mx + b
m - slope
b - y-intercept
We have the line y = 2x - 5.
The parallel lines have the same slope. Therefore we have y = 2x + b.
Put the coordinates of the point B(8, 6) to the equation:
6 = 2(8) + b
6 = 16 + b <em>subtract 16 from both sides</em>
-10 = b → b = -10
The equation of a line: y = 2x - 10.
Put the coordinates of the point A(n, 4) to the equation:
4 = 2(n) - 10 <em>add 10 to both sides</em>
14 = 2n <em>divide both sides by 2</em>
<h3>7 = n → n = 7</h3>
Answer:
Step-by-step explanation:
it is a long time I have not applied Ito's lemma
I would say the following
for 
f'(x)=2x
f''(x)=2
so using Ito's lemma we can write that
so it comes
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
