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3 years ago

9

Geometry proof help please

2 answers:

Aleks [24]3 years ago

6 0

JK = MN because of Given

∠JLK = ∠MLN because of the vertical angle theorem

JL = LN because of definition of midpoint

ΔJLK = MLN because of SAS

∠K = ∠N because corresponding angles of congruent triangles are congruent.

Hope this helps!<span />

frez [133]3 years ago

6 0

Check the picture below.

so, therefore, the triangles KLJ and NLM have a side, then another adjacent side and an angle in common, Side Side Angle. That means both triangles are congruent, and if they're congruent, so are all of their angles too.

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Enc is working as an insurance salesperson. He earns a base salary and a commission on each new policy

mihalych1998 [28]

Answer:

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Step-by-step explanation:

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3 years ago

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Nutka1998 [239]

Answer: Picking the first option and constantly adding on and on you will eventually make way more than what the second option proposes, therefore picking the first option is the obvious choice.

Step-by-step explanation:

Well let’s see it starts off slow for instance 1, 2, 4, 8, 16 and so on adding that on for a month will eventually leave you with more.

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2 years ago

How do you factor 125-x^3?

xz_007 [3.2K]

Step-by-step explanation:

We have

$125 - x {}^{3}$

First, 125 is a perfect cube because

$5 \times 5 \times 5 = 125$

and

x^3 is a perfect cube because

$x \times x \times x = x {}^{3}$

so we can use the difference of cubes identity

$( {x}^{3} - {y}^{3} ) = (x - y)( {x}^{2} + xy + {y}^{2} )$

Let say we have two perfect cubes:

64 because 8×8×8=64

and 27 because 3×3×3=27 and let subtract

$64 - 27$

we know that

$64 - 27 = 37$

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$(4 - 3)( {4}^{2} + 4(3) + 3 {}^{2} )$

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So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.

Back on to the topic,

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3 0

2 years ago

Read 2 more answers

Find the median, first quartile, third quartile, interquartile range, and any outliers for each set of data. 111, 68, 93, 88, 74

lilavasa [31]

Answer:

Q1 = 87 ;

Q2 = 102 ;

Q3 = 115 ;

IQR = 28

OUTLIER = None

Step-by-step explanation:

Given the data:

111, 68, 93, 88, 74, 152, 119, 87, 88, 105, 84, 102, 151, 115, 112

Ordered data : 68, 74, 84, 87, 88, 88, 93, 102, 105, 111, 112, 115, 119, 151, 152

Sample size, n = 15

The first quartile, Q1 = 1/4(n+1)th term

Q1 = 1/4(15+1)th term

Q1 = 1/4(16) = 4th term

Q1 = 87

The Median , Q2 = 1/2(n+1)th term

Q2 = 1/2(15+1)th term

Q2 = 1/2(16) = 8th term

Q2 = 102

The third quartile, Q3 = 3/4(n+1)th term

Q3 = 1/4(15+1)th term

Q3 = 3/4(16) = 12th term

Q3 = 115

The interquartile range, IQR = Q3 - Q1

IQR = (115 - 87) = 28

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Q2 = 102 ;

Q3 = 115 ;

IQR = 28

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3 years ago

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Mariulka [41]

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